All right, let's try again. How many people vote that this is reversible? That looks like a majority to me. Irreversible?
好的,让我们再试试,有多少人认为这是可逆的?,看上去大多数人都这么认为?
So let's actually let you try another example of solving a problem that has to do with one of the spectrums.
下面请大家来看一下另一个例子,这次是一个需要大家解决的关于光谱的问题。
Let's try it with a different equation of state, that isn't quite as simple as the ideal gas case.
考虑一个不同的状态方程,这状态方程不像理想气体状态方程那么简单。
So that's pretty good. Let's try a slightly larger example.
所以很好,让我们试试,数字大一些的例子。
So what I wanted to do is loop back, at least with a couple of things that we see recurring and very understandably so, but let's try to clear up a couple of frequently occurring issues.
所以我想要做的是回环,至少用两三个,我们看到的东西返回,并且可以理解地,让我们试着处理几个,频繁发生的事情。
That was way fewer responses than I wanted. Let's try again; what's the name of this downward sloping line that I've just drawn?
没几个人回答啊,我再问一遍,这条向下倾斜的曲线叫什么
Let's try to get that up in premises."
我们试着研究一下前提条件
Let's try that. All right.
我们来试试,好吧。
We could also, I think, well, maybe this isn't written out in terms of that convention, which sometimes it's not, so let's also try writing it, such that we have the hydrogen and the oxygen atom there.
我们也可以,我想,好吧,还有可能它不是按照惯例写的,有时候会出现这样的情况,因此,让我们把氢原子和,氧原子成键的情况也写出来。
So what we're going to do together is to figure out what these best responses look like and let's try and do that.
所以我们将一起找出,最佳对策是什么,我们一起试着找找
So let's leave these off for a moment, and now let's try that.
先把这个放在一边,看这个。
Now we've set it up as a matrix, let's try again that question I asked before.
现在我们就把这个矩阵写好了,我们现在来回答之前的问题
All right, well that's correct. So let's try and read that through.
正解,我们再从头到尾看一遍
Suppose now--harder to imagine, but let's try it-- suppose now that you are an indignant angel and you're playing against, and you know this, you're playing against an evil git.
假设你是一个愤怒天使,我知道这个对你们来说很难,但你现在知道你要和,一个自私鬼博弈
So let's try that.
好,我们开始。
So let's try and do that.
咱们来试一下
So this isn't so hard, we know that if I choose Up and there's probability 0 that the other guy is going to choose Right, that's the same as saying I choose Up and the other guy chooses, let's try it again.
这不是很难得,我们知道如果我选上的话,我对手选右的概率就是0,也就是说我选上,我对手会选择,我说错了,重新来
Also, what's the energy per photon of this red laser pointer, and then it's also worth trying a calculation dealing with intensity. So let's also try calculating the numbers of photons that would be emitted by this laser pointer, if, for example, we were to use it for 60 seconds and this were a one milliwatt laser.
同样,红色激光笔的,每个光子能量是多少,这也值得用处理强度的方法计算一下,让我们也计算一下,有多少光子会从这个激光笔射出,举个例子,如果我们使用它持续60秒,这里会有一毫瓦的激光。
So the best response for Player 1, as a function of what Player 2 chooses, q2, is just equal to the q1 hat in this expression and if I solve that out carefully, I will no doubt make a mistake, but let's try it.
这个就是参与人1的最佳对策,它是参与人2策略q2的一个函数,它和之前的q1帽那个表达式是相等的,虽然我是很仔细地计算的,还是有可能算错的,我来验证一下
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