OK? And in fact, if you look at the code up here, and it's on your handout, the very first one, x 1, right here- if I could ask you to look at it-- is a piece of code to do it. And I'm less interested in the code than how we're going to analyze it, but let's look at it for a second.

实际上，如果你看看,你们课堂发的材料上面的代码，第一页上的，就是那-,大家请看看实现的这一部分代码,我不太关心,我们会怎么解释这个代码,首先让我们先看看。

麻省理工公开课 - 计算机科学及编程导论课程节选

00 Now I say while i is less than or equal to 100, I write my code, I sleep for a second.

现在我指明当i小于等于，我写下我的代码，我休眠一分钟。

哈佛公开课 - 计算机科学课程节选

So it feels a little backward mentally perhaps, 1 but this is saying, "do this block of code as long as n is less than 1."

所以它感觉可能有点迟缓，但是它指明，“只要n小于,执行这段代码“

哈佛公开课 - 计算机科学课程节选

So this line or these lines of code up here are arguably constant time steps to say if N is less than 2 in return, that it will always take maybe one step, maybe two steps, some number of fixed CPU cycles.

如果N小于2并返回,那么这些行所对应的代码,通常只需要执行一步，或者两步，具体数字与CPU周期有关。

哈佛公开课 - 计算机科学课程节选