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And if you do so, you will end up with 1.312 mega joules per mole for this quantity K.
这样做之后，对于K常量你就能得到2,1。312百万焦耳每摩尔。
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I mean, J. K. Rowling, Lloyd Alexander, C. S. Lewis, whatever you like.
比如说，罗琳、亚历山大、路易斯，你喜欢的都行。
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And what does that say? It says, let's assume I want to do k searches of a list. OK.
如果我们假定要在列表中做k次搜索,在线性的情况下，假定是一个未排序的情况。
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What comes out of the math is that the value of k, there are multiple values, there are multiple solutions.
得到的数学结果是k的值，这有多种值，多种解法。
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So, it was having trouble and word got out that it was having trouble and the rumors started spreading in the U.K.
因此,有传闻称,北岩已陷入危机,甚至开始在英国散布
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O.K., today, what a joy. What a joy!
今天，非常高兴！
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This actually I think derives from a Greek word, "Synkope, " S-y-n-k-o-p-e, synkope.
这个术语我觉得来源于希腊语,Synkope,S-y-n-k-o-p-e
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we are going to return from exile in the 530s, o.k.?) So when we talk about the post-exilic period, we are talking about the period after the return.
我们将会回到530年左右的流放时期，好吧）,当我们说到流放后时期，我们就的是回归后的时期。
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Professor Kohli is a David K.E. professor of international affairs at the Woodrow Wilson School of public and international affairs at Princeton University.
克里教授是普林斯顿大学,威尔逊公共和国际事务学院,研究国际关系动向的教授,在学校负责,正常授课。
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10kJ/K That's the heat released, divided by minus 10 or 10 kilojoules per Kelvin, right. It's 8.2 Kelvin.
再除以-10，或,这就是8。2K，换句话说。
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It will typically look like this and the formula we say is F = - kx, where k is called "The force constant."
图像看上去一般就像这样,对应的式子是 F = - kx,k 叫做"弹性系数"
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k And over here this is the value of minus K.
这个时候我们值为。
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If I reduce that it would be 3 plus t of b minus 3, so in general 3*k+t this is 3 k plus t of b minus k. OK.
把b减去一个,在外面加个3就可以了,因此也就是。
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Well, the energy at infinity is zero -K and the energy in the ground state is minus K.
无限远处的能量值为,而基态能量值为。
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So, there was a savings bank movement, which spread from the U.K. To the U.S. in the nineteenth century and it was a philanthropic movement.
于是便有了一场储蓄银行的运动,这股风在19世纪从英国刮到了美国,这也是一场博爱运动
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Here's the problem. How do I get to the nth- er, the k'th element in the list, in this case?
如何找到第n个元素呢-,在这里，如何找到第k个元素呢？
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