So today, I want to be a little bit less abstract, if you like, and I want to look at an application.
今天的课程会不那么抽象,如果你们愿意的话,我想在这里列举一个应用案例
So if I got these two cells they would be less they would have less potential than these.
因此这些细胞它们会,它们拥有的潜能就会比较少
It says, if answer, sorry, imagine x is -16, ANS is 0 is less than -16, no. So what does it do?
对不对?让我们来看看,如果答案,对不起0,如果x是-16的话,ANS为0,小于-16吧,对?
So it looks a lot less messy if we just draw our Lewis structure like this for h c n, where we have h bonded to c triple bonded to n, and then a lone pair on the nitrogen there.
这看起来整洁了不少,如果我们把氰化氢的路易斯结构画成这样的话,这样我们就有氢与碳之间的单键和碳与氮之间三键,然后还有一对孤对电子在氮这里。
No, if I'm saving this year my consumption would be less than my income, so my consumption might be here and I would then have more next year.
错了,如果我今年增加储蓄,我的消费就会少于收入,这里表示消费,明年我就会有更多的收入
So if we lower the synergy here, not only do I contribute less effort, but you know I contribute less effort, and therefore you contribute less effort and so on.
如果我们减少协同参数,不但我会少付出努力,而且你也知道我会少付出努力,因此你也会少付出努力,以此类推
And just as there are innumerable human activities which require undistorted references if they are to be satisfied, so there are innumerable other human activities not less important which equally require distorted references or, more plainly, fictions.
就像无数的人类活动,需要真实的证据,如果要达到令人满意的效果,无数同等重要的,人类活动,也同样需要失真的参考,说得更明白点,就是需要虚构。
So if n is greater than or equal to 1 and n is less than or equal to 3, let's just judge this thing a small number arbitrarily.
所以n大于等于1,并且n小于等于,我们武断的判定它为,一个小的数字。
All right, so gamma, the gas is cooling so V2 is going to be less than it what would be if the temperature kept constant.
气体温度下降了,于是V2会比等温过程,降到相同压强时的体积要小。
n Alright. So if n is less than or equal to 1, return n. Well that's not right, right?
好吧,如果n小于等于1,它会返回,这里不对,是吧?
So, if we want to go from that stable state to that less stable state, we need to put in a certain amount of energy to our system, that difference between the free electron and the electron bound to the metal.
所以,如果我们想使电子,从稳态到达不够稳定的状态,我们需要引入一定数量的,能量到系统中,即自由电子和束缚于金属的,电子的能量差。
So the thing that I hope jumps out at you from this picture is no great guesses about figuring out this is a ?, so if the probability that the goalie's going to jump to the right is less than a ?, then the best you can do is represented by this green line, which is shoot to the right.
我希望大家都能从图中看出来,得出这一点的横坐标是?不难,如果门将扑向右路的概率,小于?的时候,此时你的最佳策略用这段绿线表示,即你应该从右路射门
All right, it's so if I looked at it, sorry, IF x is less than y, THEN check to see IF x is less than z, and if that's true, print out x is the smallest.
好,代码是这样的,对不起,是不是x比y小,然后去看看是不是x比z小,如果都为真的话,显示x为最小值。
It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.
然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于,我对这两个元素进行比较,然后返回结果就可以了,否则的话,我们就去寻找中值点,注意它是怎么实现的,首先这个指向一个列表的开头。
So given some input of N elements, first, if N is less than 2, I return immediately.
给出N个元素的一些输入,首先,如果N小于,就立即返回。
If n is greater than zero, I decided I would say, "You picked a positive number, backslash n," so put the cursor on the next line, else if n was not less than zero, I say, "You picked a negative number, backslash n."
如果n比0大,我就决定来说:,“你选择了一个整数,反斜杠n“,所以你把光标,放在下一行,另外如果n不小于0,我说:,“你选择一个负数,反斜杠n“
So if N is not less than 2, that is I have two elements or more in which case there's definitely some sorting to be done.
因此如果N不小于2,也就是有2个或更多的元素,那当然是需要做排序的。
So if P1 is less than P2--so if they're the low price firm-- if Coke is the low price firm, only Coke sells in the market.
如果P1小于P2,公司1的价格较低,如果可口可乐的价格较低,市场上将只销售可口可乐
So in this experiment here, delta p is less than zero. You need to have this whole thing greater than zero. So delta T is less than zero as well. So if you're below the inversion temperature and you do the Joule-Thomson experiment, you're going to end up with something that's colder on this side than that side.
所以在这个实验中,Δp小于零,这全部都大于零,因此ΔT也小于零,所以如果在低于转变,温度的情况下做焦耳-汤姆孙实验,最后的结果是,这边的温度比这边低。
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