Actually, what I did was used 107kJ/mol a different source so I have 107.

事实上，我使用了另一个路径,计算得到了。

麻省理工公开课 - 固态化学导论课程节选

Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.

也能改变温度，绝热指的是没有热传递，在非绝热条件下，也同样可以升温,比如用火或者热源加热，这样，q也应当与路径有关。

麻省理工公开课 - 热力学与动力学课程节选