Well, oxygen, we'll put a hydrogen here, 1 2 3 4 hydrogen here, and one, two, three, four.

如果把一个氢放在这边，另一个氢这边，然后。

麻省理工公开课 - 固态化学导论课程节选

So, I'm asking very specifically about radial nodes here, how many radial nodes does a hydrogen atom 3 d orbital have?

我问的是径向节点，这里3d轨道的径向节点有多少个？

麻省理工公开课 - 化学原理课程节选

And then this second term, if we go to the Periodic Table, 2 we will find that the value here for hydrogen is 2.2 98 and the value for fluorine is 3.98.

再算上第二个条件，翻看元素周期表，我们查处H，F电负性分别为2,2。2，3。

麻省理工公开课 - 固态化学导论课程节选

So it's going to be a sigma bond, 1s and we have oxygen 2 s p 3 and hydrogen 1 s.

它是sigma键，我们有氧2sp3和氢。

麻省理工公开课 - 化学原理课程节选

The reason that it's a sigma bond is sp3 because the s p 3 hybrid orbital is directly interacting with the 1 s orbital of the hydrogen atom, and that's going to happen on the internuclear axis, they're just coming together.

它是sigma键的原因,是因为,杂化轨道直接和氢原子1s轨道相互作用，它们作用发生在核间轴上，它们会到一起。

麻省理工公开课 - 化学原理课程节选

So what we'll do is this problem here, which is let's calculate out what the wavelength of radiation n would be emitted from a hydrogen atom if we start at the n equals 3 level and we go down to the n equals 2 level.

我们来做这个问题,让我们来计算一下,从n等于3到,等于2能级氢原子辐射的波长是多少。

麻省理工公开课 - 化学原理课程节选

First there was the observation by Michelson who back in the late 1880s had done very precise interferal metric measurements of the hydrogen lines and had observed that the 656 nanometer line 3 associated with the transition of n equals 3 to n equals 2 was, in fact, a doublet.

首先是麦克逊,在1880年底的观察,他以公制单位对氢原子的光谱线,作了准确的，无其他因素干扰的，测量,发现当n值由3变为2时,会同时得到波长为656纳米的谱线3,实际上是有两条线。

麻省理工公开课 - 固态化学导论课程节选

And then we're going to name the atomic orbitals that make it up, and it's being made up of a carbon 2 s p 3 orbital, and a hydrogen 1 s orbital.

然后我们要命名,组成它的原子轨道，它是由碳2sp3轨道，和氢原子1s轨道组成。

麻省理工公开课 - 化学原理课程节选

It's a sigma bond, - and it's going to be -- N2sp3 no. OK, it's going to be nitrogen 2 s p 3, because it's a nitrogen atom, 1s and then hydrogen 1 s.

它是sigma键，它是-,不，OK，它是，因为这是个氮原子，然后是氢。

麻省理工公开课 - 化学原理课程节选