• Now, you know with constant volume, H now it's not going to be delta H that's U straightforward to measure, it's going to be dealt u, all right.

    好,现在你们知道在体积恒定的条件下,我们得到的不是Δ,我们直接测量到的是Δ,好,但这基本上也是一样的。

    麻省理工公开课 - 热力学与动力学课程节选

  • Whereas under these conditions, these quantities, if you look at free energy change, for example at constant temperature and pressure, H you can still calculate H.

    但是,在这些条件下,这些物理量,如果我们考察自由能的变化,例如在恒定的温度和压强下,我们仍然可以计算。

    麻省理工公开课 - 热力学与动力学课程节选

  • Unfortunately, this is also call the Rydberg constant, so it's a little bit confusing. But really it means h the Rydberg constant divided by h, and that's equal to 3 .

    不幸的是,它也叫Rydberg常数,所以这可能会有点混淆,但它表示Rydberg常数除以。

    麻省理工公开课 - 化学原理课程节选

  • The force, as this weight drops is constant, mgh and so the work is just going to be m g h, h where this is h.

    当重物掉落时候的力是恒定的,因此做功就是,这段长度是。

    麻省理工公开课 - 热力学与动力学课程节选

  • This is equal to zero. So this irreversible process this Joule-Thomson process, is a constant enthalpy process. Delta h for this process is equal to zero.

    等于0。所以这个不可逆过程,也就是焦耳-汤姆逊过程,是一个等焓过程。

    麻省理工公开课 - 热力学与动力学课程节选

  • dT That means that dH is also equal to dH/dT, constant pressure dT. All right, so now I've T ot more dH/dT under constant pressure.

    也等于偏H偏T恒压乘以,现在我已经得到了在恒压,状态下的偏H偏。

    麻省理工公开课 - 热力学与动力学课程节选

  • So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.

    所以我们通过不同能量,得到不同频率,频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。

    麻省理工公开课 - 化学原理课程节选

  • And that in the case of constant volume, U in this case that's my delta u, and then I'll H add my little delta n term to get delta H.

    这是在等体情形下,此时的到的是Δ,然后我可以加上Δn的项来得到Δ

    麻省理工公开课 - 热力学与动力学课程节选

  • Because temperature is constant H only 0 cares about temperature. and that's equal to zero.

    因为温度是常数,而H只和温度有关,所以这等于0,如果这等于。

    麻省理工公开课 - 热力学与动力学课程节选

  • So if you had a high temperature, this a small compared to b. If you're negative which means that dT/dp at constant H is less than zero.

    高于反转温度,这一项相比于b很小,意味着H恒定时,偏T偏p小于零。

    麻省理工公开课 - 热力学与动力学课程节选

  • T Remember, we're trying to get delta H, p we're trying to get dH/dT constant pressure and dH/dp constant temperature. OK, these are the two things were trying to get here.

    想要得到在恒压状态下的偏H偏,和在恒温状态下的偏H偏,好的,这是两个我们,在这里想要得到的东西。

    麻省理工公开课 - 热力学与动力学课程节选

  • du But here you've got pressure constant. du, T this is du, not H here. du/dT is only equal Cv to Cv when the volume is constant, not when the pressure is constant.

    这里是压强横笛,du,这是,不是H,偏U偏,只在体积恒定时等于,而不是压强恒定时。

    麻省理工公开课 - 热力学与动力学课程节选

  • And I use the term photon here, and that's because he also concluded that light must be made up of these energy packets, and each packet has that h, that Planck's constant's worth of energy in it, so that's why you have to multiply Planck's constant times the frequency.

    我这里用光子这个词,是因为他还总结出光,必须由这些能量包组成,每个能量,包有这个h,普朗克常数代表,里面的能量,所以这就是为什么你们,要用普朗克常数乘以频率。

    麻省理工公开课 - 化学原理课程节选

  • H We also saw that dS for constant H and p was greater than zero.

    我们同样可以看到如果保持自由焓,和压强不变熵的变化dS也是大于零的。

    麻省理工公开课 - 热力学与动力学课程节选

  • What is dH/dT as a function, keeping pressure constant, what is dH/dp, keeping temperature constant?

    恒定时偏H偏T是什么,温度恒定时的偏H偏p又是什么呢?,好的,让我们解决第一个问题?

    麻省理工公开课 - 热力学与动力学课程节选

  • Adiabatic q equal to zero. It's also delta H 0 which is zero. The two didn't necessarily follow because remember, delta H is dq so p is only true for a reversible constant pressure process.

    在这个过程中ΔH等于,绝热的所以q等于0,而ΔH也等于,这两个也不一定有因果关系,因为,记住,ΔH等于dq只有在恒压。

    麻省理工公开课 - 热力学与动力学课程节选

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