This depends on the path. It tells you right here the path is constant pressure. These don't depend on the path, right. V doesn't care how you v get there. u doesn't care how you get there.
这由变化的具体路径决定,这个小脚标表明过程是恒压的,这些量都与具体路径无关,即不管是通过什么路径使得体积变化为Δ
Get out of your mind Henry V, forget the Battle of Agincourt.
忘掉亨利五世,1415年英王亨利五世于法国北部阿金库尔村以弓箭手重创兵力数倍于己的法军
If you took the derivative of this, you will get the velocity at time t, it would be: v=v0+at.
如果你对它求导,你就可以知道 t 时刻的速度,即,v=v0+at
We want to do that because we have too many variables here. We've already got dV p we'll get rid of p as an additional variable and replace it with V which is already in here.
我们之所以要那么做,是因为这儿有太多变量了,我们已经有了dV,我们要把,作为额外的变量消去,用已存在的V代换它。
D-A-V-I-D So when you get a string like D-A-V-I-D, what's really happening is inside your computer's RAM is going a byte where there's some zeros and ones.
譬如你有这么一个字符串,而在你电脑的RAM里将会变成,一个个由0和1组成的字节。
So we immediately get du at constant S and V is less than zero.
这样我们马上就得到以下结论:,在等熵,等容条件下dU必须小于零。
We'll get an expression in which there is no t; t has been banished in favor of v.
我们现在得到了一个不含t的表达式,t被v替换掉了
And the useful outcome of all that is that p we get to see how entropy changes with one of those variables in terms of only V, T, and p, which come out of some equation of state.
这样做的重要结果是,我们得到了熵随着V,T或者,其中一个变量变化的情况,这些可以从状态方程得到。
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