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If you put those together, you will get 4.
如果把它们放在一起就会得出。
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you get 4 GEs and then you get your writing II credits.
你能得到四个GE，然后你能得到写作II的学分。
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So that's here, and if I knew they were choosing Right for sure, that's the probability of 1 that they're choosing Right, and if I choose Middle I get 4, that's here.
对应的是这个点,如果说对手肯定选右,即他们选右的概率是1,此时我选中的收益是4,就是这个点
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4 6 Just as in nitrogen, we get two, four, six here, but now we have two more electrons.
对于氮，我们有，但是现在我们有两个多的电子。
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And you should know that a 2 s is larger than that, and a 3 s is even larger, and of course, hopefully as we go to 4 and 5, you would be able to guess that those are going to get even larger.
你们要知道２ｓ比这更大一点，３ｓ就更大，当然对于４和５,你们可以猜到,它们就会更大一些。
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Locally x got bound to 3, 3 I added 1 to it, whoop-dee-doo, 4 I get back a 4. But what's the value of x?
这是我想要的对吧？,在局部程序中x被赋值为，我给它加了1，我得到了？
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Sometimes it takes 4 or 5 years in order to get some level of competency.
有时候它需要4到5年才能达到一定的水平，
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And I'm also like everybody else on emails; and I'll get your emails, panic emails at 3:10 in the morning and I'll reply at 4:45. So, it goes like that.
电子邮件我和其他人一样,我会收你们的邮件,早晨3:10紧急邮件,我会在4:45回复,所以就是这样
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At its extreme what I'm think of an undergraduate Education is a four-year initiation into a life-long Club. Right now students tend to think I come to University and I leave the university. And for many Of them their sole contact is when they get a limonite newsletters and solicitations for donations.
它的极端就是把4年的本科教育,发展为终生教育,现在学生总觉得,来读大学又会马上离开,真正的接触也许只有在,收到校友新闻信和捐款征询时,才感觉到。
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And I can get out in 4 years with a major in nursing.
我在这里可以学4年的护理专业。
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And here if I choose 2 against 4, I get all the people at 1, all the people at 2, and what?
如果我选2她选4呢,我会得到立场1和2的选票
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Let's count. 1, 2, 3, 4, 5, 6, 7, 8, 9 he's going to get 10 votes, including himself there are 10 votes here.
我们数一下1233456789,他将获得10票,包括他自己的票数在内有10票
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In the former case if I choose 1 against 4, how many votes do I get?
如果我选立场1对手选立场4,我会获得多少选票
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it's an easy calculation -- we're just taking the negative of the binding energy, again that makes sense, because it's this difference in energy here. So what we get is that the binding energy, when it's negative, the ionization energy is 5 . 4 5 times 10 to the negative 19 joules.
这个计算很简单-我们,只需要取结合能的负值,同样这很容易理解，因为这就是这的能量差,所以我们得到的就是结合能,当它取负值，电离能就是5。45乘以。
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Claire Elise is going to get her own vote plus 1, 2, 3, 4, 5, 6, 7, 8, 8 votes and Beatrice is getting 1, 2, 3, 4, 5, 6, 7, how did I end up with eight, I thought I had an odd number. 1, 2, 3, 4, 5, 6, 7 there must have been an odd number before.
克莱尔·伊莉斯将获得自己的选票加上,12345678 8张选票,而比阿特丽斯获得1234567,我怎么数出8个来的,我想应该是个奇数,1234567,之前也应该是个奇数
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So, this should be pretty straight forward, 100% let's see if we can get close to a 100% on this one, which is how many radial nodes does a 4 p orbital have?
很简单,让我们来看看这题，我们是不是可以接近%,对于一个4p轨道，它有多少个节点？,给你们10秒钟？
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d1 2 3 And we can do that just going along, 3 d 1, 2 3, and the problem comes when we get to chromium here, which is instead of what we would expect, 4s23d4 we might expect to see 4 s 2, 3 d 4.
我们能做的就是继续，问题出现了,当我们来到铬元素时，它不是我们预期的那样，我们可能预期。
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Yes. Is 4 bigger than 3? Yes. Get to the end.
是的4比3大么？是的，到终点了。
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If I'm careful I should get this right 1, 2, 3, and 4 are the possible choices for Player I.
我好好画一下,这样会准确点,参与人I的可选策略从1一直到4
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s1 So for the fourth period, now we're into the 4 s 1 3d for potassium here. And what we notice when we get to the third element in 4s2 and the fourth period is 3d that we go 4 s 2 and then we're back to the 3 d's.
对于第四周期到现在我们来到钾的1,然后我们返回到,我们注意到当我们看到第三个元素,第四周期我们来到,然后我们返回到。
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So that explains probably most of the confusion here and you just want to be careful when you're reading the problems that that's what you read correctly. I think 4 everyone would now get the clicker question correct.
这可能解释了大部分人的混淆之处,你们读题目的时候一定要仔细,我相信现在每个人都能回答正确了,第三激发态，n等于。
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And seeing that it's a 4 p has two nodes - let's just write this out since not everyone did get it correct.
因为有些同学没答对,我们还是写一下,如果我们讨论的是4p轨道。
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We can plug this in further when we're talking about the visible part of the light spectrum, because we know that for n final equals 2, then that would mean we plug in 2 squared here, so what we get is 1 over 4.
当我们讨论可见光谱的时候,我们可以把这个代进去,因为我们知道n末是等于2的,这意味着我们可以。
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so in some sense it's safer, it avoids the 0, although I mean it's true it avoids the 0 but it also doesn't get the 5 and the 4.
某些情况下选下是比较安全的,因为他避免了0收益,我的意思是它的确避免了0收益,但选它也得不到5和4这连个最大收益
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08 This is 4.19. You get the E of the HF is equal to 608.
这是4。19，HF的E是。
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To get any location in memory, to get to any value of the list, I simply have to say which element do I want to get, I know that these things are stored in a particular size multiply that index by 4, add it to start, and then it's in a constant amount of time I can go to that location and get out the cell.
取得列表中的任何一个值,简单说来，想要取得列表中的任何元素,我知道这些元素存在特定的大小中,把下标乘以4，加到start上,然后定位到内存单元，并取出值就是固定的时间了,好的，如果元素以固定大小存储。
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