That in many cases, I can gain efficiency if I'm willing to give up space. Having said that though, there may still be a problem, or there ought to be a problem that may be bugging you slightly, which is how do I guarantee that my hash function takes any input into exactly one spot in the storage space?

普遍存在的增益和权衡,在许多的例子中,可以通过牺牲空间而得到效率方面的增加,话说回来，仍然存在一个问题,或者应该会有一个问题困扰着你,就是我如何保证我的哈希函数能够准确将,任一输入映射到相应的唯一的存贮空间中去？

麻省理工公开课 - 计算机科学及编程导论课程节选

Great work! Keep it up. No pain, no gain.

学得真棒！再接再厉哦！一分耕耘，一分收获。

Is there any 课堂 - SpeakingMax英语口语达人

And the reason is simply because the energy that Z we gain in terms of moving up in z, 5 so from going to z equals 4 to z equals 5, -- is actually outweighed by the energy it takes to go into this new shell, to go into this new sub shell.

原因很简单,就是因为我们通过提升，所得到的能量--从，Z，等于，4，到，Z，等于，事实上比填充到这个新的壳层,新的亚壳层，所消耗的能量更多。

麻省理工公开课 - 化学原理课程节选