So again, for both heat and work we don't get the same result. Now let's look at our special function, right. So here's path A.
所以,再一次说明,对于热量和功,我们得到的结果是不同的,现在让我们看看我们的特殊函数。
I would say, okay, this guy wants me to find a function which reduces to the number a when I take two derivatives, and I know somewhere here, this result, which says that when I take a derivative, I lose a power of t.
出题者想要我找出一个函数,它在经过两次求导后得到数字a,我知道这里的某个地方,这个结论告诉我,我每求一次导,t就降一次幂
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