Because it takes three units where there's only four choices at each position to have at least 20 unique combinations.
因为每个位点上仅有四种可能性,只有采用三个碱基一组,才能取得至少二十种不同的组合方式
How many combinations of codons are there if there's three bases and four possibilities at each base?
那密码子的组合方式到底有几种呢,三个位点,每个位点四种选择
Okay, so now we've seen four different combinations.
目前为止我们看到了四种组合
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