I could do the same thing for Player 2 to find Player 2's best response for every possible choice of Player 1.

同理对于参与人2来说,可以算出参与人1不同策略的最佳对策

耶鲁公开课 - 博弈论课程节选

Find player I's payoff is a function of what player II's effort is.

参与人I的收益是参与人II付出的函数

耶鲁公开课 - 博弈论课程节选

Identify the best responses of each player as a function of the others and find out where they intersect.

把每个人的最佳对策看成别人策略的函数,然后找出函数的交点

耶鲁公开课 - 博弈论课程节选

For each q2 that you give me or that Player 2 chooses, I want to find out and draw what is Player 1's best response.

对与参与人2的每个策略q2,我想知道参与人1的最佳对策是什么

耶鲁公开课 - 博弈论课程节选

How are we going to find out Player i's best response?

我们怎么才能找出参与人I的最佳对策

耶鲁公开课 - 博弈论课程节选

We have Player I's payoff as a function of the two efforts and now I want to find out what is Player I's best efforts given a particular choice of S2? Yeah.

参与人I的收益是两人付出的函数,那么对于某个给定的S2,怎么计算参与人I的最佳对策呢

耶鲁公开课 - 博弈论课程节选

So similarly, I would find that ?2 2 equals 1 plus B S1 and this is the best response of Player II, as it depends on Player I's choice of effort S1.

同理可得?2等于1+B*S1,?2是参与人II的最佳对策,因为它与参与人I的策略S1有关

耶鲁公开课 - 博弈论课程节选