And we find the same thing for these two atoms here, it's not actually a double bond, it's somewhere between a single bond and a double bond.

而且我们发现这两个原子的情况是一样的，它其实不是一个双键，而是介于单键与双键之间的。

麻省理工公开课 - 化学原理课程节选

If you look really carefully, you could find it was not a single line but two lines, and Bohr is silent on such matters.

如果你仔细观察的话，会发现这是两条谱线而非一条，对这一研究，波尔不得不沉默。

麻省理工公开课 - 固态化学导论课程节选

Well, if you're going to do that, you've got to be able to find what you're looking for in a page in two steps.

如果让你去实现的话，你肯定是通过两个步骤,去找你想要的网页中的内容的。

麻省理工公开课 - 计算机科学及编程导论课程节选

But what we will find is, it's more convenient to lump these two numbers into a single entity, which is called a vector.

但我们会发现,将两个数值看作一个整体会更方便,我们称之为矢量

耶鲁公开课 - 基础物理课程节选

Who else can find a way of reconciling the reaction of the majority in these two cases?

还有谁能来为两种情况中,大多数人的不同选择作出合理解释？

耶鲁公开课 - 公正课程节选

So you should remember that any time we combine 2 s orbitals, what we're going to find is if we constructively interfere those two orbitals, we're going to form a bonding orbital.

你们要记住，任何时候我们组合两个2s轨道，我们会发现,如果我们把它们相长叠加，我们会得到一个成键轨道。

麻省理工公开课 - 化学原理课程节选

We have Player I's payoff as a function of the two efforts and now I want to find out what is Player I's best efforts given a particular choice of S2? Yeah.

参与人I的收益是两人付出的函数,那么对于某个给定的S2,怎么计算参与人I的最佳对策呢

耶鲁公开课 - 博弈论课程节选

And I can find the orientation of the arrow You have the option of either working with the two components of A or with the arrow.

我也可以求得矢量的方向,你可以选择使用,A 的两个分量或者矢量图来计算

耶鲁公开课 - 基础物理课程节选

I would say, okay, this guy wants me to find a function which reduces to the number a when I take two derivatives, and I know somewhere here, this result, which says that when I take a derivative, I lose a power of t.

出题者想要我找出一个函数,它在经过两次求导后得到数字a,我知道这里的某个地方,这个结论告诉我,我每求一次导,t就降一次幂

耶鲁公开课 - 基础物理课程节选