So, once we figure out what our probability of backscattering is, we'll just raise that to the 1/2, and we'll multiply that by 12 . 20 centimeters.

所以一旦我们,知道了散射概率，我们开根号。

麻省理工公开课 - 化学原理课程节选

The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

我们可以用叫做,键序的概念来弄明白它，键序等于1/2乘以成键电子,数目减去反键电子数目。

麻省理工公开课 - 化学原理课程节选

So I want to figure out the best response of Firm 1 as a function of the price chosen by Firm 2.

我想找出公司1的最佳对策,并用公司2价格的函数表示

耶鲁公开课 - 博弈论课程节选

I'm trying to figure out; we quit when, ten until 1:00, right?

我想问一下,我们是在一点过十分下课,对吧

耶鲁公开课 - 古希腊历史简介课程节选

So then in order to figure out the complete number of valence electrons in our molecule, we just add 5 plus 4 plus 1.

那么接下来为了得到,这个分子中价电子的总个数，我们只需要将五加上四，再加上一。

麻省理工公开课 - 化学原理课程节选

If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.

如果我们来看看最后一个结构,在中间的原子是氮，我们同样可以计算出所有的形式电荷，而在这种情况下，氮为正一，碳为负二，而最后硫为零。

麻省理工公开课 - 化学原理课程节选

So this is going to be the choice of Player 1, and this is going to be the choice of Player 2, and what I want to do is I want to figure out what this looks like.

这个表示参与人1的策略,这个表示参与人2的策略,接下来我想要知道,这个函数究竟是什么样子的

耶鲁公开课 - 博弈论课程节选

So instead you'd have to maybe if you start with wavelength, go over there, and then figure out velocity and do something more like kinetic energy equals 1/2 n b squared to get there.

这时你要先从波长开始，到这，然后算出速度,然后像动能等于1/2nb平方得到这。

麻省理工公开课 - 化学原理课程节选

So what we're going to do is we're going to figure out Player 1's best response quantity to each possible choice of Player 2, and then we're going to flip it around and figure out Player 2's best response quantity to each possible choice of Player 1, and then we're going to see where those coincide, where they cross.

下面我们就需要表示出,参与人1对于2不同产量下的最佳产量,然后反过来写出,在参与人1的不同产量下,参与人2的最佳产量,然后再来看看这两者在哪里相交

耶鲁公开课 - 博弈论课程节选

So what I need to do then is I need to figure out what is Player 1's best response for each possible choice q2 of Player 2.

所以我们要先找出,在参与人2的每个可选策略q2下,参与人1的最佳产量

耶鲁公开课 - 博弈论课程节选

And if we talk about electrons or photoelectrons, again we can describe it in terms of energy, we can talk about velocity, and from there, of course, you can figure out the energy from 1/2 m v squared, and actually we can also describe the electron in terms of wavelength.

如果我们谈论电子或者光电子，我们又可以从能量的角度来描述它，我们可讨论速率，从那里，当然，你可以计算1/2，m，v2得出能量值，而且事实上我们也可以,从波长的角度来描述电子。

麻省理工公开课 - 化学原理课程节选