So this guy here gets rid of this, and I have my answer as V1 over V2 to =p2/p1 the gamma power is equal to p2 over p1.

这两项抵消掉了，于是等式,变成了^γ

麻省理工公开课 - 热力学与动力学课程节选

T1 Anyway T2 over T1 is equal to V2 over V3 to the power gamma minus one.

总之，T2除以3,等于V2除以V3的伽马减一次方。

麻省理工公开课 - 热力学与动力学课程节选