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We can also talk about it in terms of if we want to solve, if we, for example, we want to find out what that initial energy was, we can just rearrange our equation, or we can look at this here where the initial energy is equal to kinetic energy plus the work function.
初始能量是多少，也可以,写成另一种形式,我们可以把方程变形,或者我们看这里,初始能量等于,动能加功函数。
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And we know that n describes the total energy, that total binding energy of the electron, so the total energy is going to be equal to potential energy plus kinetic energy.
我们知道，n是描述总能量的，电子总的结合能，所以总能量，等于,势能加动能。
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And so what I get is the energy of the system at the equilibrium separation is given by minus z plus.
这就是通过减去z+得到得平衡分离时,我得到的能量体系。
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One is, du, u is called the internal energy dw or just the energy, is equal to dq plus dw.
其中一个是：du，u是内能,或能量，等于dq加上。
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In this case, it's called the ionization energy, plus whatever kinetic energy we have left over in the electron.
在这种情况下，它就是电离能，剩余部分将转化为,出射电子的动能。
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That is to say I can now reroute that sodium plus chlorine reaction and go a different way, but I still end up with the same change in energy.
也就是说，我可以重新定义一种,钠与氯的反应途径,从另一种途径来实现反应，但是能量的变化过程相同。
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So, I've got plus twos, zooming in at high energy against a wall of positive charge.
两个高能的正电荷,在正电荷壁垒时会遇到阻力。
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So, what we call this is the third ionization energy, or the negative of the binding energy, again of the 2 s orbital, but now it's in boron plus 2 to we're starting with.
那么我们称它为第三电离能，或者负的束缚能，还是，2，s，轨道的，但现在我们是从正二价硼离子开始的。
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Where the Gibbs free energy, TS u plus pV minus TS is H minus TS.
吉布斯自由能等于，内能u加上pV减去TS，也是自由焓H减去。
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So let's think about the energy required now to remove a 2 s electron, let's say we're removing it from boron plus 1 versus neutral boron.
那么让我们来想一想,拿走一个，2，s，电子所消耗的能量，假设一个是从正一价硼离子中拿走1,另一个是从中性硼原子中拿走。
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And what we say when we talk about the delta energy is I E 2 that this is going to be equal to i e 2, or the second ionization energy, or we could say the negative of the binding energy of a 2 s electron in b plus.
那么我们说,Δ，E，应该等于，或者说第二电离能，也就是正一价硼中，2，s，电子的,束缚能的负值。
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