I look at the rest of the list to decide what's the element to swap into the next place.
我会查看列表剩下的部分,来看看需要交换哪个元素。
But if, at any point, I get to a place in the list where the thing I'm looking for is smaller than the element in the list, I know everything else in the rest of the list has to be bigger than that, I don't have to bother looking anymore.
比当前位置数组的元素要小,我也就知道后面的数肯定,也都比我的目标数要大了,我就不用再继续进行下去了,这意味着目标数不在这个数组中,我就可以退出了。
With this, if I can assume that accessing the i'th element of a list is constant, then you can't see that the rest of that analysis looks just like the log analysis I did before, and each step, no matter which branch I'm taking, I'm cutting the problem down in half.
读取数组中的第i个元素,是个常量时间的操作的话,我也就能像以前那样得到,这个算法是对数级复杂度的分析,并且每一步不管我选择哪个区间,我都可以把问题的规模缩小一半。
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