So, for example, down here I wrote that it was n 2 and that it was h 2, but when I re-wrote the molecules up here, you saw that it's an h h single bond where it's a nitrogen-nitrogen triple bond.
比如,在这下面我写的是氮分子2,而这个是氢分子,但我在上面把这些分子的形式改写了,大家可以看到,这是一个氢与氢之间的单键,含一个氮与氮之间的三键。
Absorption is just the opposite of emission, so instead of starting at a high energy level and dropping down, when we absorb light we start low and we absorb energy to bring ourselves up to an n final that's higher.
吸收就是发射的逆过程,与从一个高能量到低能量不同,当吸收光时,我们从低能量开始,吸收能量到一个更高的能量。
In the case of Nimes, N-I-M-E-S, which was largely a Protestant town, they knocked down the wall so the Protestants of Nimes could not defend themselves against this all-conquering Catholic monarch.
以尼姆为例,那儿曾经是一座新教徒的城市,但统治者们拆毁了围墙,所以新教徒们再也无法对抗,所向无敌的天主教统治者了
By the way,I should write these things down,N?mes.
我顺便写一下这个词,尼姆
Down here, I've just got two things to merge, and then I've got things of size two to merge and then things of size four to merge. But notice a trade off. I have n operations if you like down there of size one.
但是n的大小是不同的,是吗?在这里我们只要合并两个元素,然后是合并长度为2的列表,接下来是合并长度为4的列表,但是观察一下之间的权衡关系。
We learn nothing from examining what is going on down here in n equals one shell.
必须仔细检查不然我们学不到什么的,这里n=1的壳。
How many times you can divide N by 2 before you get down to 1?
在得到1之前需要将N除以2做几次呢?
And unlike n, l can start all the way down at 0, and it increases by integer value, so we go 1, 2, 3, and all the way up.
不像n,l可以从0开始取,然后每次增加一个整数,所以我们可以去1,2,3,一直下去。
We can go all the way down -- magnesium aluminum, all the way to this noble gas, 3s23p6 argon, which would be n e and then 3 s 2, 3 p 6.
我们可以继续,镁,铝,一直到惰性气体,氩它是Ne然后。
So this is not even thinking about the other electron shielding, just if we think of the fact, all we need to think about is that the effect of going to a further away n n as we go down the table.
到现在我们甚至还没有考虑,其它电子的屏蔽效果,即使我们要考虑这个因素,我们需要考虑也就是,沿着周期表的某一列往下走,距离会逐渐变远,将起最重要的作用,actually,dominates,这一结果所产生的影响。
So what we'll do is this problem here, which is let's calculate out what the wavelength of radiation n would be emitted from a hydrogen atom if we start at the n equals 3 level and we go down to the n equals 2 level.
我们来做这个问题,让我们来计算一下,从n等于3到,等于2能级氢原子辐射的波长是多少。
So this is our final equation, and this is actually called the Balmer series, which was named after Balmer, and this tells us the frequency of any of the lights where we start with an electron in some higher energy level and we drop down to an n final that's equal to 2.
把2代入到这里,所以得到1除以,这就是我们最终的方程,这叫做Balmer系,以Balmer名字命名的,它告诉我们从高能级掉到n等于2的,最终能级所发出光的频率。
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