And in this case, the tie-breaker goes to the molecule in which the negative charge is on the most electronegative atom.

而在这种情况下，我们需要进行“附加赛“,也就是看看分子中带有负的,形式电荷的原子是不是电负性最高的。

麻省理工公开课 - 化学原理课程节选

So, in this case, we see that our formal charge is negative on the nitrogen, in this case it's negative on oxygen.

那么，在这种情况下，我们看到氮的形式电荷是负的，而在这种情况下，氧的是负的。

麻省理工公开课 - 化学原理课程节选

So, I've got this tiny volume with, in the case of gold 79 plus of charge, and I've got some electrons out here somewhere, and the vast majority of the atom is nothing.

我认为这个小体积里面，比如金的79个正电荷，电子在外面的某些地方，原子里面大部分是空心的。

麻省理工公开课 - 固态化学导论课程节选

So, we can also get into a case where we have similar values in terms of absolute values of formal charge between two different molecules we're deciding between in their Lewis structures.

我们还可能遇到另外一种情况,那就是在我们需要进行,选择的两种路易斯结构中,形式电荷具有相似的绝对值。

麻省理工公开课 - 化学原理课程节选

I am going to highlight this by calling this q1, lower case q being the charge here on the nucleus.

我要把它称作q1来进行强调，小写q是指原子核上的电量。

麻省理工公开课 - 固态化学导论课程节选

We don't actually have much charge separation in this case here.

我们在这种情况下其实没有很多电荷分开。

麻省理工公开课 - 化学原理课程节选

So what we see is that structure a is the most stable because we have the least separation of charge in the case of structure a.

因此我们看到结构，A，应该是最稳定的,因为这种情况下,分开的电荷最少。

麻省理工公开课 - 化学原理课程节选

And lower case q sub 2 is the charge on the electron.

小写q加个下标2是指电子所带电量。

麻省理工公开课 - 固态化学导论课程节选