a You know that what will happen is that heat will flow from a to b from b to c and from a to c. That's common-sense.
你知道会发生的是热量从流向,从流向,以及从流向。
You can tell if you're at all experienced with it very easily, if you go--let's say to the year 900 B.C.
而如果你对此比较熟悉的话很容易看出来,如果你去--假定去公元前九百年
They are African-and-American kids, and their coming to D.C.
他们都是非裔美籍的孩子,此次来环境保护署总部。
I mean if you chose Alpha, you're swinging from A to B-; and from Beta, swinging from B+ to C.
要是你选α,你的分数会在A到B-,选β,分数范围会在B+到C
Pseudocode is kind of an English-like syntax that's just a useful way of expressing yourself fairly succinctly, fairly computer-like but without having to worry about stupid details like whether it's Java or C or whatever.
伪码是一种类似英语的语法,可以简洁地,表达自己的意思,它与电脑类似,但是你不用担心那些愚蠢的细节,比如Java,C语言或者其他什么语言。
Well, all the way down, i guess, to C or beyond that -then you're failing.
如此排列,我想到达C或者更低时...,也就意味着你违约了
So, we start on C and then we go up to D-- a whole step.
我们从C开始,然后上升到D,一个全音级
Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.
等式两边同时乘以2,得到,2q1*=/b-q1
How far along do I have to go drop off a - c when I have slope -2b?
斜率-2b的线还要经过哪个横坐标呢
Each firm is going to produce a - c over 3b and there are two such firms.
每家公司的产量是/3b,而且市场中有两家公司
You can stack these things in C. So if you want to do if - and then rather -- let me tweak this just so simplify -- if you want to stack these things and do this in one case or that in the other, can you stack them like this?
你们才可以在C语言中使用这些东西,所以如果你想做,-让我把这个弄得更简单点-,如果你想把这些代码堆集在一起,在一个情况中,或在另一个情况中处理,你能够像这样把他们集在一起吗?
This is a file called Holloway.c. This is-- to be clear, not a program.
这里有一个文件Holloway,c,不是程序-,我们马上就要清除掉它。
What's that telling me is that if Player 2 chooses not to produce then Player 1's best response is a - c over 2b.
参与人2产量为0而参与人1最佳对策是,/2b,这能说明什么
I got to have a - c over 2b - q2 over 2.
应该是/2b - /2
It would be c times 3 in the third year, etc., Then the present value is equal to c/-- that's the formula for the value of a growing console.
在第三年它就是三倍的的三次方,现值就相当于c/,这就是上涨债务价值的公式
It'll give me q1* is equal to a - c over 2b - q1* over 2.
会得到,q1*=/2b-q1*/2
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