But if I want to do it all in one shot, what is the equivalent step I should take?
但我如果想要一步完成,那我应该用什么样的等价步骤呢
But you had the equivalent in Amsterdam as well.
不过在阿姆斯特丹也一样
p1 I said let's do this slowly enough that this p1 is in equilibrium with this p1, but not so slowly that this pressure is equivalent to that pressure.
我曾说过我们足够慢地使这边的1,与这边的p1平衡,但是没有慢到,这里的压强等于这里的压强。
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