It's one element like I claimed before it's sorted and so there's no work to be done.
当有1个元素时,在比较前就知道它是有序的,那就没必要再进行比较了。
Now, don't be distracted by the fact that they already appear to be sorted.
现在,貌似它们是有序的,但不要被这一事实干扰。
Really there's no work to be done if I am handed all in sorted order so, you know, There's no work to be done if I'm handed all of the arrays in sorted order so, you know, if I demand that you give me this assumption that the cups are already sorted and then I'll sort them for you, I mean, this is kind of a cyclical argument.
如果杯子是有序排列的,那就没必要再对它进行排序了,同样如果给出的序列本身就是有序的,那也不必再做什么,如果给出这样的假设:,杯子已经有序,但仍需要对其进行排序,这像是个循环的论点。
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