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And then the magic is really finding the right solution in the middle that combines all these needs and desires and wishes the customer has with all the technology ingredients.
关键在于，找出,中和二者方法,使其既合乎顾客需求,又在技术上可行。
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Knowing that, I'm going to say, OK, how many pigs are there, well that's just how we're, however many I had total, minus that amount, and then I can see, how many legs does that give, and then I can check, that the number of legs that I would get for that solution, is it even equal to the number of legs I started with, ah! Interesting. A return.
它将给我返回头的总数，知道了这些之后我可以说好了,有多少猪呢，无论有多少组鸡的数目，我只要用总数减去那个值,之后我就可以知道一共有多少条腿,然后再把这个值和题目中的腿数相比较，看它是否等于一开始的腿数,啊！真有趣，有一个返回值。
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I have yet to show you the solution to a wave function for the hydrogen atom, so let me do that here, and then we'll build back up to probability densities, and it turns out that if we're talking about any wave function, we can actually break it up into two components, which are called the radial wave function and angular wave function.
我还没有给你们看过,氢原子波函数的解，让我现在给你们看一下，然后再来说,概率密度，实际上,对于任何一个波函数来说，我们可以把它,分解为两部分，分别叫做径向波函数,和角向波函数。
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The answer is it will want to reform with itself, and if I have these in solution then how many reform with itself and how many reform with the molecule I'm interested probably depends on the relative concentrations of both in the solution and what conditions I have it at.
答案是质粒有可能会自己闭合,如果质粒和我感兴趣的DNA片段,都在溶液里那有多少质粒会自己合上,有多少与我感兴趣的DNA重组呢,这大概取决于两者在溶液里的相对浓度,和我让溶液处在什么条件下
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First of all, two parameters. It's OK. All it says is, when I call this, I need to pass in two parameters for this to work. All right? Now, if I want to use that, I'm going to use a second piece of code here, called Barnyard. I'm going Barnyard to read in a couple of values, convert them into integers, and then I'm going to use solve to get a solution out.
注意我得到了什么,第一，两个参数,它的意思就是我调用这个函数，我得给它输入两个参数，明白了吗？,现在如果我要使用它我得用,这里的第二段代码，也叫,我将读入一组值，将它们转化为整型,然后我会用solve得到一个解决方案。
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