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char * s1 Then I go ahead and declare a char * called s1.
然后我声明。
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And when you declare a variable, whether as an argument or as literally a local variable, they only live inside of that function.
当你声明一个变量，不论是一个参数,还是一个局部变量，它们只存在函数的内部。
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It's a little different if they buy-- suppose you own a hundred shares and they declare a 5% cash dividend,then you get $5.
但又有些不同,如果他们买进...,假设你有一百股股票,他们宣布发放5%股利,你拿到五美元
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- So in fact, if you want a super long number -- -- let me go ahead and reopen this program -- long you could declare long.
所以事实上，如果你需要一个超级长的数字-,让我们继续重新讨论这个问题-,你可以声明。
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- Then you declare a float called f and then assign it -- -- let me scroll up for the folks in front -- that give return value of GetFloat.
然后你声明一个float类型f，再赋值-,让我向上为你们回滚到-,给出了GetFloat的返回值。
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This is copy2.c. At the very beginning I, again, demand say something and then I declare s1 to be a string, aka char *, and I store in s1 the string the user types in.
这是copy2。c，在开头打印一句话，然后声明s1是一个字符串，也叫做char，*，然后把用户输入的字符串存储在s1中。
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Well, simply with the * notation at least on the way in when you declare the function called swap, you simply say this is not going to take an int and another int because that's useless.
好的，简单说，当你声明一个函数调用swap函数时,使用*符号，你可以简单说，这不能使用一个int数和另外一个int数,因为那是无效的。
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And actually, if I don't want to clobber, as we say, overwrite the value of my variable, ; I could declare another one and store the return value in Y; Y so now I have two ints in memory; X and Y, 3 one with two, one with three.
实际上，如果你不想彻底清除，像我们说的，覆盖那个变量的值，我可以申明另一个变量Y，并在Y中保存那个返回值;,现在内存中有两个int数，X和，一个的值为2，一个为。
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So there's no mention of int, and yet we've been saying for the past couple of lectures, that anytime you declare a variable, you absolutely have to specify its type.
这里没有提及int，我们在前几个演讲中,一直讨论的东西，任何时候你声明一个变量，你必须指定它的类型。
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Then I do the same thing on line two and I declare something called "y."
然后我在第二行做了同样的事情,我声明了“y“
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