Identify the best responses of each player as a function of the others and find out where they intersect.
把每个人的最佳对策看成别人策略的函数,然后找出函数的交点
I was a soccer player and I played soccer there for the four years that I was at school.
我是个足球运动员,在大学的四年里一直踢足球。
And success, as a fourteen years-old squash player, was the most important thing in my life.
成功对14岁的壁球手来说,是我生命中最重要的东西。
It's like watching the U.S. Open and thinking you're some kind of a player.
就像你看美国网球公开赛,想象自己是个选手
We learned that in this game deleting strategies that are never best response, and then deleting strategies that are never best response to anything that is a best response and so on and so forth, yielded a single strategy for each player.
我们学到了在剔除,非最佳对策的策略后,要再剔除那些在对手最佳对策下,不是最佳对策的策略,以此类推,最后每个参与人都只有一个策略了
The brain perceives all of this complex information and it processes it and it extrapolates from it the beat, but again nobody in music-- except the bass drum player in a marching band-- nobody in music ever does anything except just play the beat.
我们的大脑感知了所有复杂的信息加工后,推算出了拍子,不过没有人,除了军乐队的低音鼓手,没有人在音乐里仅仅只是打鼓点
And they have a very famous Finnish player on that team.
他们队有一个很有名的芬兰球员。
Now, we're going to listen to a piece of music here from the tradition of classical India and I thought we might have a sitar player in here.
现在,我们要听一段,传统的印度古典音乐,我原以为我们能请来一位锡塔尔琴手
And to make this more concrete, if a firm is competing against a competitor it can be pretty sure, that competitor is a pretty sophisticated game player and knows that the firm is itself.
再具体点说,如果一家公司在和它的竞争对手竞争,可以肯定其竞争对手一定很老练,这家公司当然也很老练啦
Because at this point, as in the partnership game, which there was a similar thing, as in the partnership game where the best responses intersect is where Player 1 is playing a best response to Player 2, and Player 2 is playing a best response to Player 1.
因为这一点,与合伙人博弈的情况一样,两者的情况是很类似的,合伙人博弈中最佳对策曲线的交点处,参与人1采用了回应参与人2的最佳对策,参与人2采用了回应参与人1的最佳对策
So here's Player I's payoff as a function of what Player II chooses and what Player I chooses, so we have that already.
这个就是参与人I的收益的方程,它是参与人I和II策略的函数,我们已经得到了
So more succinctly, Player I and Player II, at this point where the lines cross, Player I and Player II are playing a best response to each other.
简单来说,参与人I和参与人II,在这两条线的交点处,互相都采用的是最佳对策
So the strategies below 1 and above 2 are never a best response for Player I.
也就是说小于1及大于2的策略,都不是参与人I的最佳对策
I'll just remind us of what these functions are; it's a - c over 2b - q2 over 2 and accordingly for Player 2.
再说一遍,参与人2的方程是,/2b - q2/2
And the strategies above 2 were never a best response for Player II.
大于2的也不是参与人II的最佳对策
And all these strategies for Player II are gone, and all these strategies for Player II are gone, and what's left? A lot of scribble is left.What's left?
参与人II的这些策略被剔除了,参与人II的这些策略也被剔除了,划掉的都剔除后,最后剩什么了
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