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Because I might have written some code in which I'm expecting that integer particular variable to have an integer value.
因为我可能写了一些代码,来把一些,变量的类型，指定为。
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You've got a picture of somebody's face, it's a million pixels. Each pixel has a range of values from zero to 256. I want to hash a face with some function into an integer.
你有一个人的脸部照片，它有一百万个像素,每个像素的值范围在0到256之间,我想用某个函数将一张脸部照片。
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So at the very top, I've coded up the same thing as before: "Give me an integer between one and ten," or rather, -- "give me an integer between one and ten" -- a little different this time.
所以在顶部，我像之前那样对同样的东西进行编码：,“给我一个1到10的整数“，或者，“给我一个1到10的整数“,这次有点不同。
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Let me generalize this. In this case, my incrementer was just adding 1 to an integer, it's a pretty straightforward thing to do.
当我完成后，我不会再显示任何信息了，好，好，那么你们已经看过两个简单的例子了，让我来讲讲概念，在这个例子中。
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I give it some character. It gives me back an integer representing. It looks weird.
我输入一些字符,程序返回给我一个整数的表示。
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I'd like an integer please, a colon, and a space just for aesthetic reasons.
我想要一个整型数，一个冒号，和一个,使其更美观的空格。
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And then, if I want to find out if something's there, I do the same thing. But notice now, hash is converting the input into an integer.
然后，我想查找出某些元素是否在列表中,我做同样的事，但是现在注意，哈希是将输入转化成一个整数，所以，其思想是什么？
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If you want to output an integer or other types as we'll see.
如果你想输出一个整数，我们将学习到的其他类型。
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So with an integer, an int data type, you can store any number between 0 and 4 billion roughly.
只要有一个整数，一个int型的数据，就能储存任意一个,位于0到40亿之间的一个数。
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Right, It's just squaring an integer, is what it's doing.
对了，这个程序就是，用来求一个整数的平方的。
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So hopefully there is indeed a way to fix this, but it looks as though the division operator, the single slash is division but -- and here's a curiosity about many programming languages -- because 17 is an integer and because 13 is an integer, why do I say that?
我的确希望有一个方法来修正这个错误，但是看起来,好像那个除法操作，那个斜杠是除法,但是--对于很多编程语言来说,是挺奇怪的--因为17是一个整数,13也是一个整数，为什么我这样说？
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Give me an integer between 1 and 10."
给我一个1到10的正数“
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So I'd like an integer please.
所以我想要一个整型数。
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Pick an integer, somebody.
多少个头？来个人选个整数。
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Right, that divide is, if x is an integer and two is an integer, what's it going to do?
好，这个除法意思是，如果x是个整数而2也是个整数，那么会怎么操作呢？
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So, for example: in this case, my list is a bunch of integers. And one of the things I could take advantage of, is I'm only going to need a finite amount of space to represent an integer.
列表是一系列整数,要注意的这里的优势能够,用有限的空间来表示整数,例如，如果我想要操作。
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All right, first question. What values of x does it terminate? Again, assume x is an integer.
好，第一个问题，对于x的什么值程序,会最终终止，还是假设x为整数。
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So this declares an integer, a variable of type int called I, 0 and initializes it to zero.
所以这里声明了一个整型数，一个叫做I的整型变量，把它初始化为。
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That means starting at the first one, I'm going to do something to it. And what am I'm going to do? I'm going to take that character, convert it back into an integer, and add it into some digits. And I've done a little short hand here, which is I should have said some digits is equal to some digits plus this.
这意味着从第一个字符开始，我要对他们进行一些操作,我要去做什么呢？我要取得这个字符，然后把它转换为整数,然后加到某些数上面去,我在这里用了一些缩写,我本来应该写一个数字等于这个数字。
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I'm given an integer that's a perfect square, and I want to write a little piece of code that's going to find the square root of it. All right so I'm cheating a little, I know it's a perfect square, somebody's given it to me, we'll come back in a second to generalizing it, so what would the steps be that I'd use to walk through it?
完美平方数的整数，我想写一段代码来求这个数的平方根,好，我这儿有点儿作弊了,我知道这是一个完美的平方数了,他们给我的，我们后面会讲怎么产生这个数的，那么我想解决这个问题,需要什么步骤呢？
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So this is something that we would call an integer, or an INT. And this is something we would call a floating point, or a float.
这是我们称之为integer的类型，或者INT，这是我们,称为浮点数的类型，或者浮点。
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So this line here declares a variable, just storage space called "x" and it's of type "int," which means an integer has to go in it.
这里的这条线声明了一个变量，一个叫做“x“的存储空间，它的类型是“int“,意思是里面存储的是整数型的数据。
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Go ahead and implement with the person next to you a program that takes as input from the user an integer called F and prints out the answer of the Celsius equivalent.
继续和你旁边的人执行程序,取来自用户的整数F作为输入,然后打印出与之等价的摄氏温度的答案。
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a to the b where b is an integer.
也就是a的b次方，而b是个正整数。
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4 So even if the correct mathematical answer is 1.4 or whatever, when you divide an int by an int, you only have room in that variable, in the response for an actual integer.
所以即使那个正确的答案是4,或别的数值，当你用一个整型数除以一个整型数，在那个变量的返回值里，只有,存储一个整型数的空间。
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