Well let's see. My fall back is, I could just do linear search, walk down the list one at a time, just comparing those things. OK. So that's sort of my base. But what if I wanted, you know, how do I want to get to that sorted list? All right?
我只能做线性搜索了,一次遍历一遍列表,一个一个比较,但如果我想要,那怎样得到有序的列表呢?,现在的一个问题是,我们排序之前?
Really there's no work to be done if I am handed all in sorted order so, you know, There's no work to be done if I'm handed all of the arrays in sorted order so, you know, if I demand that you give me this assumption that the cups are already sorted and then I'll sort them for you, I mean, this is kind of a cyclical argument.
如果杯子是有序排列的,那就没必要再对它进行排序了,同样如果给出的序列本身就是有序的,那也不必再做什么,如果给出这样的假设:,杯子已经有序,但仍需要对其进行排序,这像是个循环的论点。
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