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So basically we're saying yes, we can go from point a to point c without ever going through point b.
所以我们说的是我们可以从,ａ点不经过ｂ点而到达ｃ点。
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a You know that what will happen is that heat will flow from a to b from b to c and from a to c. That's common-sense.
你知道会发生的是热量从流向,从流向,以及从流向。
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But now, imagine that we are living in the early years of a polis sometime in the eighth century B.C.
但是,现在想象一下,假如我们生活在公元前八世纪
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If you want a real world example of this, think about the third Century B.C., someone can correct me afterwards.
现实世界也有这样的例子,大概在公元前三世纪,如果我说错了请大家来纠正
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So you can think of it, if we were to just think of it as a straight line that we were going across, essentially what we're saying is that we're getting from point a to point c without ever getting through point b.
你们可以来想想看，如我我们把它想成是一条直线,我们要沿着这条线经过，这就是说我们要从ａ点,不经过ｂ点而到ｃ点。
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Again I should have said first, index 0, the first one. I can similarly go in and say I'd like all the things between index 2 and index 4. And again, remember what a b c that does. Index 2 says start a 0. 1, 2. So a, b, c.
我还是要说一遍，索引为0的元素，是第一个元素，我可以要求返回索引,2和4之前的所有元素，请记住2,是从0开始的,那么0，1，2对应的是。
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ABC The A, B, C of psychology.
心理学的。
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So they began to call this A and this B and this C and this D and this E, this F, this G.
他们开始把这叫做A,B和C,这个是D,E,F,G
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This will generalize to probability of A and B and C equals the probability of A times the probability of B times the probability of C and so on.
简单的说,A和B和C同时发生的概率,等于A发生的概率乘以B发生的概率,乘以C发生的概率,以此类推
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So let's just compare. Let's compare what C happened in path A to what happened in paths B and C. Yes?
我们比较一下沿,路径A和路径B和,所发生的事有什么不同，什么？
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The first crowd to do stuff like that, you will find, in the fifth century B.C. In Greece is a movement called the Sophistic Movement.
你们会发现第一批做这种事情的人,是在公元后五世纪的希腊人,当时兴起了一种叫诡辩的运动
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I mean if you chose Alpha, you're swinging from A to B-; and from Beta, swinging from B+ to C.
要是你选α,你的分数会在A到B-,选β,分数范围会在B+到C
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Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.
等式两边同时乘以2,得到,2q1*=/b-q1
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In this case we have a double bond between a and b, and in this case we have it between b and c.
在这种情况下，我们在，A，与，B，之间有一个双键，而在这种情况下，双键在，B，与，C，之间。
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If there's no heat flow between the b and c, then I can say all right, a and c were the same temperature.
如果在与之间没有热量流动，那么我就可以说，好吧与处于相同的温度。
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In fact, we have some claim, and a Roman writer later on, that there was a treaty back in the eighth century B.C.
实际上,之后一个罗马作家,写到过一些声明,公元前八世纪在埃维厄岛几个城邦之间
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In the years of the Mycenaean period, roughly from 1600 to 1100 or so B.C., you are dealing with a largely unified culture.
在大约公元前一千六百年,至公元前一千一百年,迈锡尼文明时期,你将看到一个高度统一的文化
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Well, the way we can reason things out from the evidence we have suggests that Greek-speaking peoples came down into the area around the Aegean Sea, perhaps around 2000 B.C., about a thousand years later than the emergence of the Minoan civilization at Crete.
根据现在我们掌握的资料推断,讲希腊语的人群主要集中在爱琴海附近,大概在公元前两千年左右,在米诺斯文明出现在克里特岛大概一千年后
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Hesiod, whom I have not mentioned to you before, a poet who we think to have lived around 700 B.C., very early in the history of the polis, wrote one of his poems called, Works and Days.
赫西奥德,我之前跟你们提到过的,是一个生活在公元七百年左右的诗人,那还是在城邦历史的初期,创作了一首名为《工作与时日》的诗歌
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And the last one in the major pattern is a half step from B to C.
大调模式的最后,是一个从B到C的半音级
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They had these little leftovers in there and that's why we end up with these small distances between B and C That's a big step.
他们还有一些剩余,这就是为什么,B和C之间有一小段距离,这是一个大音级
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What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.
2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b
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I have 3 q1* is equal to a - c over b; and finally divide by 3 q1* is equal to a - c over 3b.
q1*= /b,最后两边同除以3得,q1*=/3b
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She costs C for sure, that's a wash because B, the way we've worked things out, B was $2, C was $1, So B/2-C is a wash.
她承担C的成本,收益是零,因为B,按我们设定的金额,B是2美元,C是1美元,所以B/2-C是零
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Well, the monopoly quantity was a - c over 2b and the competitive quantity was a - c over b, just to remind you of those, they're on our picture.
垄断产量是/2b,完全竞争产量是/b,提示大家一下,这几点都在图上呢
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