So we have a total of 2, 4, 6, 8, 10 valence electrons, so I'll make sure I count to 10 as we fill up our molecular orbitals here.

我们一共有2，4，6，8，10个价电子，所以我一边填一边要确认,我数到10。

麻省理工公开课 - 化学原理课程节选

And yet if a computer can only count up to 2 billion or maybe 4 billion, I mean, what do you then do?

如果一台计算机只能够支持20亿,或者40亿，那我们该怎么办？

哈佛公开课 - 计算机科学课程节选

I can't count correctly, 1, 2, 3, 4, 5, 6, is he actually the center guy here?

我可能数错了,123456,他是这行最中间的那个人吗

耶鲁公开课 - 博弈论课程节选

And also I wanted to mention in terms of checking your Lewis structures, regardless of what they are, you should always go back and I had 10, and then count 2, 4, 6, 8, 10, because you always need to make sure you have the same number of valence electrons that you calculated in your actual structure.

我还想提一点关于检查,你的路易斯结构的建议，不管它们是什么，你总是应该回去检查一下,我有十个，然后数一数，二，四，六，八，十个，因为你总是需要确保实际价电子的数量,与你在结构中算出的数量相等。

麻省理工公开课 - 化学原理课程节选

Let's count. 1, 2, 3, 4, 5, 6, 7, 8, 9 he's going to get 10 votes, including himself there are 10 votes here.

我们数一下1233456789,他将获得10票,包括他自己的票数在内有10票

耶鲁公开课 - 博弈论课程节选

So what do you do when you're a kid and you want 3 to count a little faster than 1 and 2 and 3 and 4 what is the simplest thing you do?

因此当你还是个孩子的时候,你想数得比1，2，3，4快一些3,最简单的方法是什么？

哈佛公开课 - 计算机科学课程节选