0 So if you want to come and see me Monday 3:30 to 4:30, I am just down the hall.
如果你们要来见我,就在周一的3:30到4:,我就在大厅下面。
For the carbon, we start with 4 valence electrons, we have 0 lone pair electrons minus 4, and we end up with a formal charge of 0.
对于碳,我们从四个价电子开始,我们有零个孤对电子,再减去四,最终我们有零个形式电荷。
And he gets, you are absolutely right, 00163 it is not 4.0, it is 4.00163. Take that.
他得到的结果是,你完全是对的,不是4。0,是4。
we learned that the average number of romantic relationships for people to take positive psychology in 4 years is between zero and one.
我们了解到上积极心理学课的人,在4年里恋爱次数的平均数在0到1之间。
Middle does best against Right, after all, 4 is bigger than 0 and 4 is bigger than 2, so Middle does best against Right.
选中是右的最佳对策是吧,因为,4大于0,4大于2,所以选中是右的最佳对策
Here's 0, 1, 3, ah-ha, here's 4, 5, 6 what is there?
这里是0,1,3,啊哈,这里是4,5,6,哪里是什么东西?
to .4, so .2 is here in the middle; that's .2.
到0.4,那么0.2在中点,这就是0.2
Again I should have said first, index 0, the first one. I can similarly go in and say I'd like all the things between index 2 and index 4. And again, remember what a b c that does. Index 2 says start a 0. 1, 2. So a, b, c.
我还是要说一遍,索引为0的元素,是第一个元素,我可以要求返回索引,2和4之前的所有元素,请记住2,是从0开始的,那么0,1,2对应的是。
So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.
键序等于1/2乘以,总的成键电子数,也就是4,减去反键电子数,也就是4。,所以最后得到键序为0。
So with an integer, an int data type, you can store any number between 0 and 4 billion roughly.
只要有一个整数,一个int型的数据,就能储存任意一个,位于0到40亿之间的一个数。
Let's do this from 0 to .4.
这里是0到0.4
No, instead we have to click other amount at bottom right there, when we have to input 4-0-0 in this screen 4-0-0 after consulting visually the little cheat sheet on the device itself it tells you in a very long chart how much one pass costs so we multiply and type in 4-0-0, we hit enter.
不,然而我们必须点击,右下边的这个,当我们需要在这个屏幕上,输入0,通过咨询那个设备上小说明,它在一个很长的图表上,告诉你,每一站需要多少钱,我们加起来,输入了4-0-0,点击输入。
, okay. So 1 plus 1/4 of 0 is 1, so if Player II chooses 0, player I's best response is to choose 1.
是1,因为1+0/4=1,参与人II选0时I的最佳对策是1
Then, if n = 100--now I'm going to label this x differently, I'm now going to show the normal bell-shaped curve and I'm going to do this from 0 to .4.
如果n=100,现在我得重新标x值,我现在要画正态分布的钟形曲线了,在这儿用0到0.4
Now I'll print L 2. Kind of what you'd guess, but here's the interesting question: if I say L 1 is assigned 0, L 1 sub is assigned 4, I'll print L 1.
然后我将显示下L2的内容,你,们猜猜这个有趣的问题:,如果我将L1赋值为4的话,再去显示下L1,会怎么样呢?
so in some sense it's safer, it avoids the 0, although I mean it's true it avoids the 0 but it also doesn't get the 5 and the 4.
某些情况下选下是比较安全的,因为他避免了0收益,我的意思是它的确避免了0收益,但选它也得不到5和4这连个最大收益
You could choose any real number in the interval .
你可以选择0到4间的任意实数
Because as you'll soon find, when you're writing programs 0 that aren't just four lines long but are 40 or 400 which very quickly becomes easy, you'll find that even you the next morning have no idea what this code does for whatever reason, and just having some English comments is a huge boon to comprehension for yourself and others.
你们自己写程序时就会发现,用40行甚至400行代码来代替繁杂拥挤的4行代码0,将会让事情简化许多,你会发现,即使由于某些原因,你不知道如何写代码,先写些注释,于人于己,都是好事,易于理解嘛。
So the strategy choices, we're not going to do it in hours, let's just normalize and regard these choices as living in 0 to 4, and you can choose any number of hours between 0 and 4.
我们用小时数来表示策略吧,用0到4的数字来标记这些策略,你可以从0到4中任选工作的小时数
So we said B was somewhere between 0 and 1/4, let's draw the case for B equals 1/4.
我们之前也说过B在0到1/4之间,这里我们绘制B=1/4的情况吧
We'll assume that B lives between 0 and a 1/4 and it's known, I just want to be able to vary it later.
假设B是0到1/4之间的已知量,我希望一会能改变一下这个数据
You can search obviously by any of the fields up top by days ; of the week you want a class; days of the week you don't want a class; grad level or undergrad level, faculty scores that are 4.0 and higher, ; course overall scores that are 4.0 and higher; and a whole number of other features including synchronization with Google calendar.
你可以按日期来搜索网页上的任一科目,以决定哪天去上课,哪天不去上课;,研究生课程或本科生课程,教师打分为4分或更高的课程,课程总学分为4分或者更高的课程;,当然很多其他选择方式,包括Google同步日历。
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