So, if we hybridize just these three orbitals, what we're going to end up with is our s p 2 hybrid orbitals.

我们会看到现在有3个未配对的电子，可以成键。

麻省理工公开课 - 化学原理课程节选

So it's trigonal because we have these three atoms that are bound to the central atom here, and if you picture it, it's actually shaped like a pyramid.

这里三角形是因为,我们有3个原子核中心原子成键，如果你画它，它就是金字塔形的。

麻省理工公开课 - 化学原理课程节选

We see three bonding pairs so this is a triple bond, indeed a multiple bond.

我们看到3对成键电子所以这是一个三重键，它确实是多重键。

麻省理工公开课 - 固态化学导论课程节选

So if we take a look at nitrogen here, what you'll notice is we have thre available for bonding, - and we already have our lone pair -- one of our orbitals is already filled up.

如果我们看一下氮原子，我们注意到我们可以成3个键，我们已经有一个孤对-,其中的一个轨道已经被填满了。

麻省理工公开课 - 化学原理课程节选

So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.

我们知道它是，因为我们有1，2，3，4个成键，减去2个反键，它的一半就是键序为1。

麻省理工公开课 - 化学原理课程节选

So what we'll have here is a trigonal planar case, and you can see that we only have three electrons that are set for bonding, so we'll add three hydrogens, and for b h 3, we'll get a stable structure here.

让电子劲量远离的时候，不用考虑它,这个例子是平面三角形，你可以看到，只有3个电子可以成键。

麻省理工公开课 - 化学原理课程节选

That's what we call when we have three bonding atoms and one lone pair.

这是当我们有3个成键电子,和一个孤对时这样称它。

麻省理工公开课 - 化学原理课程节选

So if you picture this as our s p 2 carbon atom where we have three hybrid orbitals, and then one p y orbital coming right out at us.

如果你把这想象成sp2碳原子,这里有3个杂化轨道，然后一个py轨道朝向我们。

麻省理工公开课 - 化学原理课程节选

So we end up with 3 s p 2 hybrid orbitals, so we can think about what would happen here in terms of bonding, and if we think about how to get our bonds as far away as possible from each other, what we're going to have is the trigonal planer situation.

因为现在sp2轨道有1/3的s特征，2/3的p特征，而不是3/4。,我们最后得到3个sp2杂化轨道，我们可以想象,成键时会发生什么，如果我们考虑。

麻省理工公开课 - 化学原理课程节选