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So, here's the syllabus: two big blocks, first block general principles of chemistry, 1 and that's the same whether you take 3.091 or 5.111 or 5.112.
这就是教学大纲，两大块，第一部分是化学的通则，关于这点，我们的课程1,还有，5。111课程以及，5。112课程都是一样的。
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And frankly it would be incredibly time-consuming and tedious for me, to count this room full of people old school style-- 1, 2, 3 and so forth.
坦白说，按学校的老办法一个人一个人的数,1个，2个，3个……,对我来说极其费时费力。
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The payoff of 2 against 3 is all the people at 1, all the people at 2, so it's 20%.
如果对手选3而我选2我会得到,立场1和2的全部选票,一共20%
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So the 3 s 1, or any of the other electrons that are in the outer-most shell, those are what we call our valence electrons, and those are where all the excitement happens.
它们是经常发生激发情况的,那也是我们所看到，我们称之为价电子，它们是经常发生激发情况的。
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So, that's the kind of stuff: a little bit of background about myself. So now, 1 let's talk about the perspective of 3.091 All of this will be posted. You can take notes.
就是这些事情，我自己的,一点背景介绍，现在，我们谈谈这门课程的远景1,这些都会放到网站上去，你们可以记笔记。
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If we take item 2, 1 then, well, the index after that will of course be And the available weight will be 3.
如果我们装了2号物品，然后，它之后的索引号当然是,我们还剩下3磅。
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So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.
我们知道它是，因为我们有1，2，3，4个成键，减去2个反键，它的一半就是键序为1。
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And the second point is of radius 3 and angle 1, which is up about there.
半径为2然后角度为1的一个点,也就是差不多在这儿，我认为为了确保我做的是。
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*t t of n minus 1 is 3 plus 2 t of n minus 2.
加上。
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So 2 against 1 gives me 90% of the votes, 3 against 1 gives me what?
我选立场2他选1,我得90%选票,要是我选立场3对手选1呢
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You would minimize your losses; you'd get 0 or -1 instead of -3 or 1.
你能最小化你的损失,你得到0 -1而不是-3 1
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If I choose 1 against 3, what share of the vote do I get?
如果我选立场1,对手选立场3,我能获得多少选票
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So, last time I gave a reading of the creation accounts that are in Genesis 1 to 3. These are two very different stories but their placement side by side suggests the possibility of a joint reading. Nevertheless they are very different in character and today I want to focus in on the second creation story.
上次我们读了《创世纪》一到三章中,关于记述创造的，两个不同的故事,尽管他们是不同的两个故事,却经常放在一起阅读,今天，我会着重介绍第二个故事。
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d1 2 3 And we can do that just going along, 3 d 1, 2 3, and the problem comes when we get to chromium here, which is instead of what we would expect, 4s23d4 we might expect to see 4 s 2, 3 d 4.
我们能做的就是继续，问题出现了,当我们来到铬元素时，它不是我们预期的那样，我们可能预期。
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Item 1 has a weight of 3.
号物品重量是。
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If people in the room choose randomly between 1 and 100, then the average is going to be around 50 say and two-thirds of 50 is around 33, 33 1/3 actually.
如果大家在1到100之间随机选择,平均数会是50左右,而50的2/3大概是33,确切地说是33 1/3
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The payoff from choosing 3 against 4 is going to be all the people at 1, all the people at 2, and all the people at 3, for a total of 30%, which again is bigger.
当对手选4我选3的收益,就是立场1的选票,加上立场2和立场3的选票,一共是30%,立场3收益更多
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s So, we would actually take an electron out of the s, 3 d 3 4 s 1 which gives us 3 d 3 and then 4 s 1.
轨道，The，s。,因此，我们应该拿走s，轨道上的一个电子，然后得到。
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I'm gonna zoom in a little more and notice it's pretty much 1, 2, 3, 4, 5, 6, 7, 8, 9 lines of code and that's kind of rounding up because of the white space.
我现在放大一点，大家会看到，2，3，4，5，6，7，8，9行代码，多亏了空格,这些代码才能看起来如此美观。
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So it turns out that the average in this class, the average choice was about 13 1/3, which means two-thirds of the average was 9.
这个游戏的最终结果,平均数大概是13又1/3,它的2/3是9
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In particular, if the other candidate were to choose position 1, I would get a higher share of the vote choosing 2 than I would have done if I had chosen 3.
如果对手选择立场1,我选立场2会比选立场3,得到更多的票数
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So we know that 2 is not dominated, and particularly not dominated by 3, When you delete the dominated strategy of 2 dominating 1, or 1 being dominated, when you delete that and 10, then it is.
我们知道选立场2并不是劣势策略,它并不劣于选立场3,当你剔除劣于策略2的劣势策略1,或者说立场1处于劣势,当你剔除策略1和10之后,2就变成劣势策略了
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And then we're going to name the atomic orbitals that make it up, and it's being made up of a carbon 2 s p 3 orbital, and a hydrogen 1 s orbital.
然后我们要命名,组成它的原子轨道，它是由碳2sp3轨道，和氢原子1s轨道组成。
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The reason that it's a sigma bond is sp3 because the s p 3 hybrid orbital is directly interacting with the 1 s orbital of the hydrogen atom, and that's going to happen on the internuclear axis, they're just coming together.
它是sigma键的原因,是因为,杂化轨道直接和氢原子1s轨道相互作用，它们作用发生在核间轴上，它们会到一起。
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