We need to know not only what are the primitives, but how do we make things meaningful in that language.

我们不仅需要知道什么是基本类型，还要知道我们在那种语言中,怎样使其变得有意义。

麻省理工公开课 - 计算机科学及编程导论课程节选

Because it's so important. And I should add and also under reversible work, where the external pressure is equal to the internal pressure.

而且我还要说应该在外部压强,和内部压强相等的,可逆过程中引入它。

麻省理工公开课 - 热力学与动力学课程节选

But in fact, I have to go there, and when going there, I have to reconceive of not just where I was, what I was doing, but in part who I am.

而事实上，我必须前进，并且当我在前进中，我不仅必须重新审视，我在哪里，在干什么，还要审视我是谁。

普林斯顿公开课 - 人性课程节选

It has two irons that are involved in doing the chemistry, so it includes transition metals.

反应中有两个铁原子参与,因此她还要了解过渡金属。

麻省理工公开课 - 化学原理课程节选

Right? If that was the case in that code, then my complexity is no longer log, because I need linear access for each time I've got to go to the list, and it's going to Lisp be much worse than that.

这里的复杂度不再是对数的了，因为每次在列表中，查找需要线性访问,可能还要糟糕,其实，有些编程语言，如。

麻省理工公开课 - 计算机科学及编程导论课程节选

On the other hand, there are many other considerarions in the military action.

另一方面，军事行动中还要考虑其他问题。

普林斯顿公开课 - 国际座谈会课程节选

Why do people stay in relationships that are violent?

为什么还要在暴力中逆来顺受？

耶鲁公开课 - 心理学导论课程节选

And that's what he did. And for the point of view of France, they emerged from the war with the reality that they are in victory a weaker nation than Germany is in defeat.

他就是这么干的,从法国这边来看,他们在战后的现实中发现,他们作为一个战胜国,比德国一个战败国还要弱小

耶鲁公开课 - 1871年后的法国课程节选

The fiber intake is affected not only by what particular foods people pick but how much processing is done of the foods they have, where some of the fiber in foods is specifically processed out.

纤维素的摄入量,不仅取决于人们选择的食物,而且还要看食物的加工过程,有些纤维素在食物在加工过程中流失了

耶鲁公开课 - 关于食物的心理学、生物学和政治学课程节选

Now we're going to I'm going a bit slow here but I'm going to use this method next time to introduce you to the most important class, sorry, the most important game we're going to see in the whole course.

接下来我们,我放慢一点,在下一讲我还要用这个方法,我要向大家介绍最重要的课程,抱歉,是整个课程中最重要的博弈

耶鲁公开课 - 博弈论课程节选

Now remember that only appears in DNA and appears in RNA, and so can also form a hydrogen binding pair with .

还要记住T只出现在DNA中,而U出现在RNA中,U和A也可以通过氢键结合就可以了

耶鲁公开课 - 生物医学工程探索课程节选

Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.

好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4

耶鲁公开课 - 博弈论课程节选