Actually, what I did was used 107kJ/mol a different source so I have 107.

事实上，我使用了另一个路径,计算得到了。

麻省理工公开课 - 固态化学导论课程节选

Now remember, we went through before how it's a state function but to calculate it, you'd need to find a reversible path, along which you can figure this out.

请记住，我们不需要知道它是怎样的一个态函数,只计算就可以了，你需要找到一条可逆路径，沿着这条路径就能算得这个结果。

麻省理工公开课 - 热力学与动力学课程节选

I'm going from V2 to V2 dv - what do you think this integral is? Right, W1 so this is easy part, zero here.

这样才保证了过程的可逆性,下面来计算，路径1的功。

麻省理工公开课 - 热力学与动力学课程节选

So if I worry about energy I have a pretty good chance of extracting out these heat capacities, right, and I don't have to worry about exactly which path and I can really mix things up.

而能量与热容有密切的关系,从能量就可以就算出这两个热容，我不需要考虑到底是哪一条路径,可以随意计算。

麻省理工公开课 - 热力学与动力学课程节选

I take V1 to V2 first, keeping the pressure constant at p1, then I take p1 to p2 keeping the volume constant V2 at V2. Let's call this path 1.

容易计算的路径，第一条路径，是首先保持压强不变,体积从V1压缩到。

麻省理工公开课 - 热力学与动力学课程节选

So any point I pick on that path will be equal to p1, V1 to the gamma.

也就是说路径上面任取一个点,计算p，V^γ

麻省理工公开课 - 热力学与动力学课程节选

If you want to calculate a change in delta u.

我们计算Δu的路径。

麻省理工公开课 - 热力学与动力学课程节选