So if we add them all up, there should be no net charge on the molecule, if the molecule is neutral.
因此如果我们把它们都加起来,这个分子上应该没有净电荷,如果这个分子是中性的话。
So now we're just counting up our orbitals, an orbital is completely described by the 3 quantum numbers.
所以现在我们只要把这些轨道加起来,一个轨道是由3个量子数完全确定的。
All around. If you plug in the numbers, you will end up with an uncertainty 15% in the momentum as being on the order of 15%.
所有,如果你把数字都加起来,你将得到一个关于动量的不确定度,约为。
We have to add it all up so it's not just numbers, three against one; it's also all of those people at home.
得把这些加起来考虑,所以就不只是这个数字,三比一;,还要加上这三人的家人。
A kind of addition approach to values of wholes may not always be correct.
一种把所有价值加起来的方法不一定一直正确。
Same thing. Add up all the changes.
一回事,把所有的变化量加起来
Now, I prefaced this a few minutes ago about saying Professor Guttag wasn't going to like me.
结束点返回x坐标,然后把它们加起来。
We are going to have coefficients on this, and they will add up.
我们添加一些系数以后,就把他们加起来。
You might think, well, that's just a matter of adding up the goodness of life and subtracting the badness of death and summing whatever it comes to.
你可能会想,不就是把生命的好处加起来,再减去死亡的坏处,然后相加得出一个结论么。
You can't just add up all the pleasures and subtract the pains, or add up all the accomplishments and subtract the failures, or add up all the knowledge and subtract the ignorance and deception.
你不能只是把快乐加起来然后减去痛苦,或者仅是把成功相加再减去失败,或者把学问相加再减去蒙昧和欺骗。
But then, I combine i times Ax with i times Bx, because that's the vector parallel to i, with the length Ax.
然后我把 i ? Ax 和 i ? Bx 加起来,因为这是平行于 i,模长为 Ax 的矢量
We add up the goods, subtract the bads-- whatever our favorite list is-- and we come to our best educated guess about the rival evaluations of not just lives as a whole, but chunks of lives.
我们把好事加起来减去坏事-,不管我们最喜欢哪些事-,我们不但可以据理推测,一生期间其他生活的价值,还能推测某段时间其他生活的价值。
That's clear. If I add them, I'll get a vector parallel to i with lengths Ax + Bx.
这很明显 如果把他们加起来,就得到一个平行于 i,模长为 Ax + Bx 的矢量
Add up all the pleasures, subtract all the pains.
把所有快乐加起来减去所有痛苦。
Then add them, as shown here.
然后像这样把他们加起来
应用推荐