As I keep moving down, that part gets smaller, it's not always the initial length of the list, and you're right. But if you do the sums, or if you want to think of it this way, if you think about this more generally, it's always on average at least the length of the list.

等等，随着移动，剩下的部分越来越小，并不是初始那么长了，如果你算一算，或者你这么想，你考虑更一般的情况，平均下来至少是列表的长度。

麻省理工公开课 - 计算机科学及编程导论课程节选

So if everyone else reasons that way then everyone in the room would choose a number like 33 or 34, and in that case, the average would be what?

如果其余的每个人都那么想的话,如果每个人都会选择33或者34,那种情况下,平均数会是多少

耶鲁公开课 - 博弈论课程节选

Good, so even if everyone in the number-- everyone in the room didn't choose randomly but they all chose a 100, a very unlikely circumstance, but even if everyone had chosen 100, the highest, the average, sorry, the highest two-thirds of the average could possibly be is 66 2/3, hence 67 would be a pretty good choice in that case.

好的,如果每个人,教室里的每个人不是随机选择数字,而是全选了100,这好像不太可能,但如果每个人真的都选了100,就是最大的书,那平均数,抱歉,平均数的2/3会是66又2/3,此情况下67应该是个不错的选项

耶鲁公开课 - 博弈论课程节选