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It will be the first two hours of the allotted time we won't go the whole 3 hours, OK?
一共是2个小时,我们不会用完三个小时对吧？
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I think it'll start at 2 p.m.
我想大概是下午2点吧。
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Hence the title of this slide all right so 2, we've got you two paired off?
这个幻灯片的标题没说错吧，2个人吗，我们已经为你们两两配对了？
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Okay. To one servant the master gave five talents. You remember this story To one servant the master gave five talents, to another he gave two, and to a third servant he gave one talent.
你们还记得这个故事吧,主人给了一个仆人5枚金币，他给了另外一个2枚，第三个给了1枚。
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And so we can actually think about how do we calculate what the dissociation energy should be for h 2, so let's go ahead and do this.
因此，我们其实可以想到应该如何计算,氢分子的离解能，那么我们开始做一下吧。
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Well, Fahrenheit came along and thought, well, you know, 7-1/2, that's kind of silly; 22-1/2 that's, kind of silly So let's multiply everything by four.
然后华伦海特来了，他想，7。5，听起来有些犯傻;,22。5，那也够傻的,我们还是把所有的东西乘以四吧。
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This is infinity. Let's call this 3, 2, 1.
它是无穷大的，我们叫它3，2，1吧。
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And then I could do things like again, say, okay having done, that let me just run it here, run that, so I've now got polar point 1, and polar point 2.
然后给它们赋值半径和角度，然后我可以进行刚才的操作，也就是说，对刚才的笛卡尔坐标进行的操作，让我们来运行下它吧，运行下，现在我有一个极坐标点。
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Middle does best against Right, after all, 4 is bigger than 0 and 4 is bigger than 2, so Middle does best against Right.
选中是右的最佳对策是吧,因为,4大于0,4大于2,所以选中是右的最佳对策
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The idea of putting wheels on suitcases goes back only to 1972 and it was Bernard Sadow who invented-- this is amazing, right--the wheeled suitcase and he got a patent on it.
在行李箱上加轮子的想法,可以追溯到1972年2,是伯纳德？沙度发明的-,这很神奇，对吧,并且他凭此获得了专利。
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But the point is Reagan supported that effort and that made all the difference, and it took a lot of courage Reagan was going to take the recession in 1982 He was willing to support Volker no matter what to get the inflation down ... Alright, so... Interest rates in the summer of 1980 were quite high Yes, they were.
但是，里根力挺了这次货币改革,这才是重点，下这样的决心不容易,里根本打算在1982年来狠抓经济衰退2,他很信任沃尔克,为了降低通胀率，可以不惜一切代价,好吧，那么。,1980年夏天，银行利率已经相当高了,没错，确实如此。
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Game 2: "Pick a number." everyone got this? Anyone not got this?
游戏2,"选数字",你们都有吧
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And if I chose 2 against 3, what do I get? I get 20, I get all the people at 1 and I get all the people 2, so I get 20%, so we're okay again.
如果我选立场2他选立场3,我会得到20%的选票,立场1和立场2的选票都归我,所以是20%,大家都明白了吧
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6 Well again, we can go to our ones column, twos, four, eight, 16, 2 damn, 32. So we can go to 32 128 and then we can go to 64, and then 128, 1 2 3 4 5 6 7 8 and this gives me 1, 2, 3, 4, 5, 6, 7, 8.
好吧，再一次回到一位，二位，四位，八位，该死的，32，等等，所以我们可以找到32位2,再64，然后，那么我们就有了。
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No, we can't. Because if l equals 1, we can not have m sub l equal negative 2, right, because the magnetic quantum number only goes from negative l to positive l here.
不行，因为如果ｌ等于１,ｍｌ的值不可能等于－２，对吧，因为磁量子数的值,这时只能从－１到１
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So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?
我能够除以多少次2呢？,直到我得到的长度不超过2么？,对数次，对吧？就像刚才那位同学说的那样？
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People should feel free to correct my arithmetic because it's often wrong; 90 right? Two-thirds of 90, whoops, what do I need, start again.
我要是算错了要提醒我,我总算错,90对吧,90的2/3,我说错了
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So the payoff from choosing 1, let's start against 2.
我们先看看我选立场1,我们先从选立场2开始吧
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These 2 are going to come together like this, and the first bond that we're going to form is going to be a sigma bond, right, so we see that here. If we're looking head on, we see they form a sigma bond.
它们两个会靠近到一起，首先会形成的是,一个sigma键，对吧，我们在这里可以看出来，我们看到它们形成一个sigma键。
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I'm going to have 2 still, and then this S1 is going to become a 1, and this S1 here is going to become a plus B S2, everyone happy with that?
还保留,S1求导后是1,这里的S1会变成B*S2,大家都会吧
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