But the reality that we know from our quantum mechanical model, is that we can't know exactly what the radius is, all we can say is what the probability is of the radius being at certain different points.

我们不可能准确的知道,半径是多少，我们只能说，它在不同半径处，的概率是多少，这是,量子力学。

麻省理工公开课 - 化学原理课程节选

Yeah, it was a good film. I mean, I don't know how much of it was accurate or not.

它是一部好电影。我的意思是，我不知道有多少内容是准确的。

英国电影的魅力 - SpeakingMax英语口语达人

But odds are it's not sufficient just to get it from the user, I, the human need to be handed whatever this function got from the user in some form.

如果只是从用户，我这里获取，好像有点不太准确，我们得交出,该函数从用户那里得到的一切信息。

哈佛公开课 - 计算机科学课程节选

All right. I tried it on 2, I surely didn't expect a precise and exact answer to that but I got something, and if you square this, you'll find the answer kept pretty darn close to 2.

好，我试试求2的平方根,我当然不希望得到一个完全准确的答案了,但是我得到了一个近似值，试试将这个数平方一下,你会发现结果和2相当接近。

麻省理工公开课 - 计算机科学及编程导论课程节选

Those have too many inaccuracies because they're just too old.

太旧了，有许多不准确的地方。

耶鲁公开课 - 新约课程节选

So essentially, each of these orbitals come from linear combinations of all of the original orbitals, and it's hard to picture exactly how that happens, but one that you can at least start to get an idea is if you think about combining the 2 s and the 2 p z here, which is not quite accurate because of course, we're combining all of them.

本质上，这些轨道每个都来,自原来所有轨道的线性组合，我们很难想象这是怎么发生的，但你们可以至少有个概念,如果你们考虑2s和2pz轨道的结合，这当然是不太准确的，因为我们要把所有的都组合起来。

麻省理工公开课 - 化学原理课程节选

Probably I shouldn't have said it's a two-step process 'cause it's a three-step process to actually write and run it, and the third step is just going to be to run it.

也许我不应该说它是个两步完成的程序,准确来讲，应该是三步，前两步--写，第三步--运行。

哈佛公开课 - 计算机科学课程节选

It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.

我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数，但是你们可以看到在两个case中。

麻省理工公开课 - 计算机科学及编程导论课程节选