So what we've discovered from this relationship dq that du at constant volume is equal to dq v.

从这个关系式里我们发现,恒体积时的du等于恒体积时的。

麻省理工公开课 - 热力学与动力学课程节选

T p V I've got three variables, T, p and V.

一共有三个变量：

麻省理工公开课 - 热力学与动力学课程节选

D-A-V-I-D Well, if I've got a five-letter word like D-A-V-I-D, well, that's like five bytes and yet we only have the ability thus far in this class to return one thing at a time I can't return five bytes to you, but wait a minute, those bytes by nature of a computer are just stored in RAM.

好的，如果有5个字母的单词，如，那是5个字节,我们只能返回一个东西,而不能返回5个字节，等一下，这些字节被计算机本能地,存储在内存中。

哈佛公开课 - 计算机科学课程节选

v The weight, w, and v, these are the two vectors we've seen here.

重量是w和价值，这是我们看过的向量的两个值。

麻省理工公开课 - 计算机科学及编程导论课程节选

So we've got a I chord built on the first degree of the scale, a V chord built on the fifth degree of the scale, a IV chord built on the--a IV chord built on the fourth degree, and a VI chord built on the sixth degree.

这样我们就有了建立在第一音级上的I和弦，第五音级上的V和弦，第四音级上的IV和弦，以及第六音级上的VI和弦。

耶鲁公开课 - 聆听音乐课程节选

Normally I couldn't do that Vdp because this term would have p dV plus V dp, but we've specified the pressure is constant, so the dp part is zero.

一般情况下我不能这么写,因为这一项会包含pdV和，但是我们已经假定压强为常数，所以包含dp的部分等于零。

麻省理工公开课 - 热力学与动力学课程节选

We want to do that because we have too many variables here. We've already got dV p we'll get rid of p as an additional variable and replace it with V which is already in here.

我们之所以要那么做,是因为这儿有太多变量了,我们已经有了dV，我们要把,作为额外的变量消去，用已存在的V代换它。

麻省理工公开课 - 热力学与动力学课程节选

Which we've expressed now in terms of S and V, S and p.

我们把他们写成S和V以及S和p的函数。

麻省理工公开课 - 热力学与动力学课程节选