It gets really kind of trippy if you wanna output a backslash, \ you can't just use the backslash, \\ you need to use backslash backslash because otherwise a single backslash is confused with the so called escape character.
如果你想输出一个反斜杠,估计又得迷糊了,实际上,你不能直接用,而是要,否则一个\可能会被误认为,是转义字符。
- So this is where recursion gets a little trippy-- certainly initially, and that you have to kind of keep diving deeper, deeper, deeper into the problem.
在这儿就会觉得递归有点迷糊了-,起初,你必须一层一层地,深入到问题中。
Well, turns out that with arrays, not to make this too trippy too soon, but Arg V bracket something is a string, you can also use square bracket notation to go to a specific letter in a string, because little teaser a string is just an array.
好的,结果用那个数组,不要使这个很快引起幻觉,但是Argv什么的,是一个字符串,你也可以用方括号定位到,字符串中的一个特定的字母,因为一个字符串只是一个数组。
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