And then the magic is really finding the right solution in the middle that combines all these needs and desires and wishes the customer has with all the technology ingredients.

关键在于，找出,中和二者方法,使其既合乎顾客需求,又在技术上可行。

斯坦福公开课 - 戴尔CEO-Michael.Dell谈创业和发展课程节选

STUDENT: So, how do you come to a conclusion as to which you should use then, if you can determine the size based on solution, or based on input, so how do you decide?

学生：所以，你怎样决定你该用,哪个来算呢？现在如果你可以选择是，基于解决方案的大小，还是基于输入的大小，你应该怎样决定呢？

麻省理工公开课 - 计算机科学及编程导论课程节选

Then there is what I would characterize as the Christian solution.

还有就是我称之为基督教的解答

耶鲁公开课 - 古希腊历史简介课程节选

I have yet to show you the solution to a wave function for the hydrogen atom, so let me do that here, and then we'll build back up to probability densities, and it turns out that if we're talking about any wave function, we can actually break it up into two components, which are called the radial wave function and angular wave function.

我还没有给你们看过,氢原子波函数的解，让我现在给你们看一下，然后再来说,概率密度，实际上,对于任何一个波函数来说，我们可以把它,分解为两部分，分别叫做径向波函数,和角向波函数。

麻省理工公开课 - 化学原理课程节选

You've probably seen agar plates, if you smear a solution that's contaminated with bacteria on it, then that bacteria will grow on this agar rich medium and you'll get many, many copies of the bacteria that you've smeared at low density onto the plate.

你们大概见过琼脂培养基,如果将有细菌的溶液涂抹在培养基上,细菌就会在富含琼脂的培养基上生长,你会得到许多许多细菌,即使你只涂抹了低浓度溶液

耶鲁公开课 - 生物医学工程探索课程节选

> David: Yes, if you really, if you want to reimplement the solution from last where whereby it was buggy, you can absolutely say take the address of x then go there, thereby undoing all of the work you just did.

>，大卫：是的，如果你的确，如果某个地方有bug，你想要重新,实现那个解决方案，你绝对可以通过x的地址，定位到那里去，然后撤销你刚做的所有工作。

哈佛公开课 - 计算机科学课程节选

Knowing that, I'm going to say, OK, how many pigs are there, well that's just how we're, however many I had total, minus that amount, and then I can see, how many legs does that give, and then I can check, that the number of legs that I would get for that solution, is it even equal to the number of legs I started with, ah! Interesting. A return.

它将给我返回头的总数，知道了这些之后我可以说好了,有多少猪呢，无论有多少组鸡的数目，我只要用总数减去那个值,之后我就可以知道一共有多少条腿,然后再把这个值和题目中的腿数相比较，看它是否等于一开始的腿数,啊！真有趣，有一个返回值。

麻省理工公开课 - 计算机科学及编程导论课程节选

The answer is it will want to reform with itself, and if I have these in solution then how many reform with itself and how many reform with the molecule I'm interested probably depends on the relative concentrations of both in the solution and what conditions I have it at.

答案是质粒有可能会自己闭合,如果质粒和我感兴趣的DNA片段,都在溶液里那有多少质粒会自己合上,有多少与我感兴趣的DNA重组呢,这大概取决于两者在溶液里的相对浓度,和我让溶液处在什么条件下

耶鲁公开课 - 生物医学工程探索课程节选

First of all, two parameters. It's OK. All it says is, when I call this, I need to pass in two parameters for this to work. All right? Now, if I want to use that, I'm going to use a second piece of code here, called Barnyard. I'm going Barnyard to read in a couple of values, convert them into integers, and then I'm going to use solve to get a solution out.

注意我得到了什么,第一，两个参数,它的意思就是我调用这个函数，我得给它输入两个参数，明白了吗？,现在如果我要使用它我得用,这里的第二段代码，也叫,我将读入一组值，将它们转化为整型,然后我会用solve得到一个解决方案。

麻省理工公开课 - 计算机科学及编程导论课程节选