SdT This has minus T dS minus S dT, but the dT part is zero because we're at constant temperature.
这一项包含负的Tds和,但是dT的部分等于零,因为温度为常数。
TdS It comes from the fact that dq reversible is T dS, pdV and dw reversible is minus p dV.
这个结论来自于:可逆过程下dq等于,做功dw等负的。
SdT So we have dA is minus S dT minus T dS.
我们得到dA等于负TdS减去。
SdT So dG is dH minus T dS minus S dT.
所以dG等于dH减去TdS再减去。
pdV So, du is T dS minus p dV.
即du等于TdS减去。
So all that's left is negative T dS is less than zero.
只剩下TdS小于零。
We'll substitute that in, and the T dS terms are going to cancel.
将其代入,消去TdS项。
This time, the T dS terms are going to cancel.
这次TdS会被消去。
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