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It wasn't until 1645 at the age of thirty-six or thirty-seven that Milton would publish his first volume of poems, which he titled simply Poems.
直到1645年他36或37时,弥尔顿才出版了第一部诗集，就叫《弥尔顿十四行诗集》
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T So we know that T dS/dT at constant volume is Cv over T, T and dS/dT at constant pressure is Cp, over T.
在恒定压强下定压比热容Cp乘以dT除以,所以在恒定体积下dS/dT等于Cv除以，在恒定压强下dS/dT等于Cp除以。
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STUDENT: You can't exceed the volume that the knapsack can hold.
学生：你不能超过背包,所能容纳物品的体积。
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If there were just-- if you were trying to create a positive reaction of antigens and it showed up naturally wouldn't it create this reaction anyway in terms of your body would create antibodies like the secondary response volume to antibodies?
如果这里仅有,如果在自然条件下,尝试建立抗原的阳性反应,抗体这是否会像这样反应,以你身体为例,你的身体是否会产生,同二次免疫一样的抗体浓度
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OK, so for a constant volume process, du we can write du, partial derivative of dT u with respect to T at constant V, dT, dv plus partial derivative of u at constant V, dV.
好，对于一个恒定体积的过程，我们可以写出,等于偏u偏T，V不变，加上偏u偏V，T不变。
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In other words, if we don't have to worry about entropy or volume equilibrium is achieved when energy is at a minimum.
换句话说，如果我们不担心熵,和体积的平衡,那么能量就得是最小的。
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The molar volume is being changed a little bit trying to make things collide with each other, they can't occupy the same volume.
摩尔体积发生了很小的改变,如果你试图使气体分子间相互碰撞，他们不能占据同一个位置。
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I don't need to tell you the volume here, because you've got enough information to calculate the volume.
这里我不需要告诉你体积，因为你已经获得了足够多的信息,来计算体积。
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This is an example where the external pressure here is kept fixed as the volume changes, but it doesn't have to be kept fixed.
在我们举的这个例子中,外界压强不变，气体体积改变。
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And this volume, temperature and pressure doesn't care how you got there. It is what it is.
另一个状态,也有一组确定的体积。
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It didn't care what the volume was doing.
而与容积无关，理想气体的。
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It doesn't care what the volume is doing.
它与体积无关，只与温度有关。
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That is, in real life, the variables that you'd normally control aren't some combination of entropy and these variables, but really their temperature, volume and pressure, any couple of those, might be what you'd really have under experimental control.
在生活中，我们所能控制的,不是熵和其他变量的组合，而是温度，体积，压强，以及其中的两两组合,这些才是试验中所能控制的。
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In this case, V = /P. Have two quantities and the number of moles gives you another property. You don't need to know the volume. All you need to know is the pressure and temperature and the number of moles to get the volume.
以及气体的摩尔数,就可以得到第三个量,知道压强，温度和气体的,摩尔数就可以推导出气体的体积,这称为状态方程,它建立了状态函数之间的联系。
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Negative volume doesn't make any sense.
负的体积也同样没有意义。
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I mean, if the energy is lower to occupy a smaller volume, then if I have this room and a bunch of molecules of oxygen, and nitrogen and what have you in the air, and there are weak attractions between them, why don't they all just sort of glum together and find whatever volume they like.
我的意思是，如果占据小的体积会使能量降低，如果我有这样一个空间,和一些氧气，氮气和其他空气中有的气体，并且分子之间还有微弱的相互作用，为什么他们不黏在一起,然后占据他们所想要占据的体积。
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So we're going to start with a mole of gas, V at some pressure, some volume, T temperature and some mole so V, doing it per mole, and we're going to do two paths here.
假设有1摩尔气体，具有一点的压强p，体积，温度，我们将让它，经过两条不同的路径。
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du But here you've got pressure constant. du, T this is du, not H here. du/dT is only equal Cv to Cv when the volume is constant, not when the pressure is constant.
这里是压强横笛，du，这是，不是H，偏U偏,只在体积恒定时等于，而不是压强恒定时。
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