The ideal gas constant doesn't change, temperature doesn't change, and so v we just have minus nRT integral V1, V2, dV over V.

理想气体常数不变，温度也不变，因此,是负的nRT，积分从v1到v2，dv除以。

麻省理工公开课 - 热力学与动力学课程节选

The reason for inexact doesn't mean it's a crummy measurement, t means that it's path dependent, and so the value of this integral depends on how you get from one to two.

这是因为它是,与积分路径有关的，因此这里的积分值，取决于从一端到二端的,具体路径。

麻省理工公开课 - 热力学与动力学课程节选

Going around in a cycle the integral of dq over T is less than or equal to zero.

对一个循环过程作dq除以T的积分,小于等于零。

麻省理工公开课 - 热力学与动力学课程节选

/T We've got Cv integral from T1 to T2, dT over T is equal to minus R from V1 to V2 dV over V.

左边是Cv乘以，从T1到T2对dT积分。

麻省理工公开课 - 热力学与动力学课程节选