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It has to be,I think,in way, reciprocal and symmetric."
VOA: standard.2009.11.16
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The second way to have something that is net nonpolar is to have spatially symmetric disposition of polar bonds.
第二种构成,需要空间非极性,就是需要极性键的空间对称分布。
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So, somehow we have to figure out a way to take orbitals that are non-symmetric, and convert them into orbitals that are symmetric.
所以有时我们需要找到一个方法,让不对称的轨道，转变为对称的轨道。
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Just to point out in passing, up to now, we've been looking mostly at symmetric games.
顺便说一下,到目前为止,我们所学的大部分是对称博弈
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It makes sense to draw the wave function as a circle, because we do know that 1 s orbitals are spherically symmetric.
把波函数画成一个圆是有道理的，因为我们知道1s轨道是球对称的。
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And, I know I need to come up with four symmetric equi-length bonds, and let's just see, let's draw the structure here.
我想我们需要,4个对称的等长的键，让我们画出CH4的结构。
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Now, it's not going to be symmetric is it, because there's two fluorines and two chlorines.
现在，它将不会对称，因为有两个氟原子和两个氯原子。
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We somehow have to take hydrogen, attach it to carbon, and we have to make it symmetric, and we have to make it nonpolar.
我们需要把H接到C周围，而且我们需要让它是对称，且非极性的。
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There's no particular reason why games have to be symmetric.
博弈未必都是对称的
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And, it's going to be symmetric.
现在是对称的了。
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The graph to the left, this is the s orbital, symmetric.
在左边的图是对称的S轨道，对称的。
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Now I could go through again and do exactly the same thing for Player II, but I'm not going to do that because everything's symmetric.
如果我照此计算同理可得参与人II的,我就不算了,因为都是对称的
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Actually, we can do it a little better than that, since we know the game is symmetric, we know that S1* is actually equal to S2*.
实际上我们能得出更多,因为我们知道这个博弈是对称的,我们知道S1*=S2
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