You actually need to kind of do this and then you can swap these two numbers but it requires 50 percent more memory.
你实际上需要这样做,然后才能交换两个数字,但是它需要多50%的内存。
5 6 1 2 3 So it's 4, 5, 6 comma 1, 2, 3 that are passed into swap and that's why those same numbers end up in A and B. Yeah?
所以这里是,这就是为什么这些数字最终在a和b中,请说?
应用推荐