He's here to heal. Child of the cosmos, Mind traveling through Warm sands and subway tracks Humming lullabies in broken Arabic, like"Ahibak,akhi"*(*ahibak,akhi: I love you,my brother) And it's been far from easy On my clumsy days;

VOA: special.2009.04.17

s1 I have a variable called s1 and it's char * of type char * so here we go.

我有一个变量,它的类型是。

哈佛公开课 - 计算机科学课程节选

S**t, I mean. It's pretty bad. I mean.

我的意思是，非常糟糕。

机会之地，伦敦 - SpeakingMax英语口语达人

Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.

等式两边同时乘以2,得到,2q1*=/b-q1

耶鲁公开课 - 博弈论课程节选

So if Player I chooses S1*, Player II will want to choose S2* since that's her best response.

所以当参与人I选择S1*时,参与人II就会选择最佳对策S2

耶鲁公开课 - 博弈论课程节选

If Player II is playing S2*, Player I will want to play S1* since that's his best response.

如果参与人II选择S2,参与人I就会选最佳对策S1

耶鲁公开课 - 博弈论课程节选