• We put all of this over the Rydberg constant, which is 2 . 1 8 times 10 to the negative 18 joules, and we want to raise this all to the 1/2.

    除以里德堡常数,我们想把这些所有的再开方,所以我们最后。

    麻省理工公开课 - 化学原理课程节选

  • So let's actually just simplify this to the other version of the Rydberg constant, since we can use that here.

    除以n初始的平方,我们把它简化成,另一种形式的Rydberg常数。

    麻省理工公开课 - 化学原理课程节选

  • So now we have that energy is equal to the negative of the Rydberg constant divided by n squared.

    我们可以把能量方程大大简化,现在能量等于负的Rydberg常数除以n平方。

    麻省理工公开课 - 化学原理课程节选

  • We can also figure out the energy of this orbital here, and the energy is equal to the Rydberg constant.

    我们同样可以知道,这个轨道的能量,它等于,Rydberg常数。

    麻省理工公开课 - 化学原理课程节选

  • Unfortunately, this is also call the Rydberg constant, so it's a little bit confusing. But really it means h the Rydberg constant divided by h, and that's equal to 3 .

    不幸的是,它也叫Rydberg常数,所以这可能会有点混淆,但它表示Rydberg常数除以。

    麻省理工公开课 - 化学原理课程节选

  • So what we need to do here is use the Rydberg formula, and actually you'll be given the Rydberg formulas in both forms, both or absorption and emission on the exams.

    我们需要用到Rydberg公式,事实上,在考试时,我们会给你们Rydberg公式的两种形式。

    麻省理工公开课 - 化学原理课程节选

  • Negative Rydberg over what?

    负的Rydberg常数除以什么?

    麻省理工公开课 - 化学原理课程节选

  • The negative of the Rydberg constant now divided by 2 squared.

    负的Rydberg常数,除以2的平方。

    麻省理工公开课 - 化学原理课程节选

  • So, essentially when we're talking about these equations up here, all we're doing is talking about the regular Rydberg formulas, but instead we could go back and re-derive the equation for any one electron atom, which would just mean that we put that z squared term in the front.

    所以本质上,当我们讨论,这些问题时,我们说的是常规的,Rydberg公式,但对任何其他单电子原子,我们不用,从头再推到,而是仅仅把,z平方项放在前面。

    麻省理工公开课 - 化学原理课程节选

  • So, it's negative Rydberg constant over n squared.

    它等于负的Rydberg常数,除以n平方。

    麻省理工公开课 - 化学原理课程节选

  • We're going to get to more complicated atoms eventually where we're going to have more than one electron in it, but when we're talking about a single electron atom, we know that the binding energy is equal to the negative of the Rydberg constant over n squared, so it's only depends on n.

    我们以后会讲到,更加复杂的情况,那时候,不只有一个原子,但当我们讲,单个原子的时候,我们知道结合能,等于,负的Rydberg常数,除以n平方,所以它仅仅由n决定的。

    麻省理工公开课 - 化学原理课程节选

  • So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.

    我们可以发现有效的z等于n的平凡,乘以电离能除以里德堡常数,这些所有再开方,所以等于n乘以,除以RH整体的平方根。

    麻省理工公开课 - 化学原理课程节选

  • So, sometimes you'll find the Rydberg constant in different forms, but just make sure you pay attention to units because then you won't mess them up, because this is in inverse seconds here, the other Rydberg constant is in joules, so you'll be able to use what you need depending on how you're using that constant.

    有时候你们会发现Rydberg常数,会写成不同的形式,但你们要注意,它的单位就不会弄错了,因为这里是秒的倒数,而另一个Rydberg常数是焦耳,所有你可以根据你要怎么使用,这个常数来选择你需要的常数。

    麻省理工公开课 - 化学原理课程节选

  • So let's do a sample calculation now using this Rydberg formula, and we'll switch back to emission, and the reason that we'll do that is because it would be nice to actually approve what we just saw here and calculate the frequency of one of our lines in the wavelength of one of the lines we saw.

    让我们用Rydberg公式,做一个例题,我们回到发射上,这么做是因为这样,可以用我们看到的波长,来验证我们计算的频率。

    麻省理工公开课 - 化学原理课程节选

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