Find the best response function by differentiating this and maximizing the function for every q2, so we could just... Good, so what we're going to do is, all right good, we're going to... We're trying to maximize.

求导得出q2取最大值的情况下,参与人1最佳对策是q2的一个函数,说得很好,接下来,我们要求出最大值

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So I want to figure out the best response of Firm 1 as a function of the price chosen by Firm 2.

我想找出公司1的最佳对策,并用公司2价格的函数表示

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What is Firm 2's best response as a function of q1?

1的函数即公司2的最佳对策是什么

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What will Player II's best response look like as a function of Player I's choice in the same picture?

在同一个图像里面怎么表示,参与人II的最佳对策是I策略的函数

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Now conversely, how do we find Firm 2's best response as a function of q1?

反过来如何由q1求公司2最佳对策的方程

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So at this point I've found player 1's best response as a function of q2.

就能得出参与人1最佳对策是q2的函数

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Okay, so this is Firm 1's best response as a function of q2.

公司1的最佳对策是q2的函数

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I've found Player 2's best response as a function of q1, and the way I did it, just remember, the way I did was I applied a little bit of 112 and high school calculus, so that's your single variable calculus.

以及参与人2的最佳对策是q1的函数,而且我们用到的数学知识,只是稍微与112和高中微积分有关,仅仅是单变量微积分的知识

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So the expression I wanna draw first of all is the best response of Player I as a function of S2 and we agreed that that was given by 1 plus 1/4 now, 1 plus 1/4 S2.

首先我们想要绘制的表达式是,参与人I的最佳对策是S2的函数,我们都知道它等于1+S2/4

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So the best response for Player 1, as a function of what Player 2 chooses, q2, is just equal to the q1 hat in this expression and if I solve that out carefully, I will no doubt make a mistake, but let's try it.

这个就是参与人1的最佳对策,它是参与人2策略q2的一个函数,它和之前的q1帽那个表达式是相等的,虽然我是很仔细地计算的,还是有可能算错的,我来验证一下

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